Question

What is the length of a hypotenuse of a triangle if each of its legs is 4 units

Answer 1

Answer:

$\boxed{c = 5.7 units}$

Step-by-step explanation:

Using Pythagorean Theorem:

=> $c^2 = a^2+b^2$

Where c is hypotenuse, a is base and b is perpendicular and ( a, b = 4)

=> $c^2 = 4^2+4^2$

=> $c^2 = 16+16$

=> $c^2 = 32$

Taking sqrt on both sides

=> c = 5.7 units

Answer 2

Answer:

5.65 units

Step-by-step explanation:

Given,

Base ( b ) = 4 units

Perpendicular ( p ) = 4 units

Hypotenuse ( h ) = ?

Now,

Using Pythagoras theorem to find length of hypotenuse:

${h}^{2} = {p}^{2} + {b}^{2}$

Plugging the values

${h}^{2} = {4}^{2} + {4}^{2}$

Evaluate the power

${h}^{2} = 16 + 16$

Calculate the sum

${h}^{2} = 32$

$h = \sqrt{32}$

$h = 5.65 \: units$

Hope this helps..

Best regards !!