100g of ammonia releases 271.18 kJ of heat.
<u>Explanation:</u>
Given:
N₂ reacts with H₂
The reaction is:
2N₂ + 3H₂ → 2NH₃ + 92.2 kJ
According to the balanced reaction:
2 X 17g of ammonia releases 92.2 kJ of heat
34g of ammonia releases 92.2 kJ of heat
100g of ammonia will release = kJ of heat
= 271.18 kJ
Therefore, 100g of ammonia releases 271.18 kJ of heat.
Answer:
V = 144 pi or approximately 452.16
Step-by-step explanation:
The volume of a cylinder is given by
V = pi r^2 h where r is the radius and h is the height
V = pi (6)^2 4
V = pi (36)4
V = pi *144
V = 144pi
We can approximate pi by 3.14
V = 3.14*144
V =452.16
5/6
divide 25 by 5 and divide 30 by five. its their gcf
Step-by-step explanation:
34−1.9 + 1234-1.9 + 12
Find the common denominator.
Click to see fewer steps ...
Write −1.9-1.9 as a fraction with denominator 11.
34 + −1.91 + 1234 + -1.91 + 12
Multiply −1.91-1.91 by 4444.
34 + −1.91⋅44 + 1234 + -1.91⋅44 + 12
Multiply −1.91-1.91 by 4444.
34 + −1.9⋅44 + 1234 + -1.9⋅44 + 12
Multiply 1212 by 2222.
34 + −1.9⋅44 + 12⋅2234 + -1.9⋅44 + 12⋅22
Multiply 1212 by 2222.
34 + −1.9⋅44 + 22⋅234 + -1.9⋅44 + 22⋅2
Multiply 22 by 22.
34 + −1.9⋅44 + 2434 + -1.9⋅44 + 24
Combine the fractions.
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Combine the fractions that have a common denominator.
3−1.9⋅4 + 243-1.9⋅4 + 24
Multiply −1.9-1.9 by 44.
3−7.6 + 243-7.6 + 24
Simplify the numerator.
Click to see fewer steps ...
Subtract 7.67.6 from 33.
−4.6 + 24-4.6 + 24
Add −4.6 - 4.6 and 22.
−2.64-2.64
Divide −2.6-2.6 by 44.
−0.65-0.65
Answer:
2.576
Step-by-step explanation:
Given :
Confidence level (α) = 99%
Z(1 - α)/2 = Z(1 - 99%)/2
Z1%/2 = Z1%/ 2
Z0.5% = Z0.005
Z(0.99 + 0.005) = Z0.995
Using the Z distribution table ; locate the z value for the proportion 0.995 ; this corresponds to approximately 2.57
Similarly, using the Invnorm calculator function :
Invnorm(0.995) gives a Zscore of :
2.576