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nevsk [136]
3 years ago
11

Consider the equation 40x - 25y = 15

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

A) 8x - 5y = 3

Step-by-step explanation:

To create infinite solutions, the equation has to be the same line

First we can reduce the equation by dividing by 5

40x -25y =15

40/5 x -25/5 y =15/5

8x-5y =3

This is the same line , so if this is the second equation, it will give us infinite solutions

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How does the number of zeros in the product eight and five thousand compare to the number of zeros in factors? Explain.
Flura [38]
8X5000 is 40000. There's three zeroes in5000 and no zeroes in 8, yet there are 4 zeroes in the answer. This is because you must multiply the non-zeroes, and then add the zeroes from your factors. 8 times 5 is 40, add 3 zeroes to get 40000.
Hope this helps!
7 0
3 years ago
2x + 3y = 9 solve for x
lutik1710 [3]

Answer:

X=9/2-3/2

Step-by-step explanation:

1.Move the variable

2x=9-3y

2.Divide both side

X=9/2-3/2

4 0
3 years ago
Find the zeros of the function by factoring 3x^2+ 10x=8​
Wittaler [7]

Answer:

x=\frac{2}{3}, -4

Step-by-step explanation:

hope this helps!

6 0
3 years ago
Simplify fully 16x÷2xy
kogti [31]

Answer:

so you divide 16x÷2xy=8/y

which also same as 8y-¹

8 0
2 years ago
Read 2 more answers
What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?
AlladinOne [14]

Answer:

  -1

Step-by-step explanation:

See the attachment for the polynomial long division. The constant in the quotient is -1.

_____

Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.

That could be a first guess in a "guess and check" solution approach.

<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).

<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2

Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.

6 0
3 years ago
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