Consider the equation 40x - 25y = 15
1 answer:
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Step-by-step explanation:
Given that,
Amy jogs 1/3 of a mile in 1/15 of an hour and john takes 1/30 of an hour to jog 1/5 of a mile.
Speed of Amy,
Speed of John,
John will jog farther in one hour as he is moving with faster speed. The speed of John is 1 mph more than Amy.
Answer:
a) A student travelling to school on public transport: 15/52 or 0.231
b) A student walking to school: 16/52 or 0.308
c) A student not cycling to school: 43/52 or 0.827
Step-by-step explanation:
Total people = 52
Travel Method Frequency
Public Transport 12
Car 15
Cycle 9
Walk 16
Find the relative frequency of.
The formula used will be:
a) A student travelling to school on public transport:
Given Frequency: 12
Size of sample space: 52
Apply formula:
Fraction = 12/52
Decimal = 0.231
b) A student walking to school
Given Frequency: 16
Size of sample space. 52
Apply formula:
Fraction = 16/52
Decimal = 0.308
c) A student not cycling to school.
We will consider all students except those who cycle.
12+15+16 = 43
Given Frequency: 43
Size of sample space. 52
Apply formula:
Fraction = 43/52
Decimal = 0.827