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Novay_Z [31]
3 years ago
13

Please explain to me to have a better understsning. . .​

Mathematics
1 answer:
dem82 [27]3 years ago
7 0

For the first one:

m is the slope, or how much the line goes up compared to goes right.  In this case, the line goes up 40 every time it goes right 10.  We write this as a fraction so 40/10, which simplifies to 4.  Therefore the equation would be y = 4x.

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Which of these strategies would eliminate a variable in the system of equations?
natali 33 [55]

Answer:Multiply the top equation by -3 , then add the questions .

Step-by-step explanation:

6 0
3 years ago
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8^x times 2^(4-x) = 1<br> Find x.<br> With detailed steps.
Dafna1 [17]

Answer: x= -1

Step-by-step explanation:

In mathematics when you have bases that are the same while multiplying you add the powers. In this case we do not have the same bases so we are going to make it look like 8 is 2. So we sort of simplify it. So we get 8 and put into like 2^4. We do not eliminate the power x that was already there though. So we will have 2^4x × 2^4-x. So like I said earlier we add the powers. Soo we will have

  1. 4x +4-x
  2. 4x-x=1
  3. 3x+4-4 =1-4
  4. 3x/3 = -3/3
  5. x= -1
<h2>Hope that helped!</h2>
7 0
2 years ago
If f(x)=2x+5, then f(4) represents what
RSB [31]
<span>f(x)=2x+5
then
</span><span>f(4)=2(4) +5 = 8 + 5 = 13

hope it helps</span>
6 0
3 years ago
Please help and will give brainliest.
valkas [14]

Answer:

The battle that resulted in both a Confederate victory and the death of General “Stonewall” Jackson was

Step-by-step explanation:

The battle that resulted in both a Confederate victory and the death of General “Stonewall” Jackson was

6 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
2 years ago
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