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3 years ago

I Do not know what to do ANYONE help plz

Mathematics

1 answer:

Fudgin [204]3 years ago

8 0

Answer:

for circle in circle: 75π

circle in square: 64-16π

note that answers are in exact form, since I don't know how the answer should be written (exact or decimal etc.)

Step-by-step explanation:

for circle in circle, we see that smaller circle (white circle) has radius 5 and big circle has radius 10. therefore we can find area of shaded area by doing

area of big - area of small

10²π - 5²π = 100π - 25π = 75π

circle in square, applying the same method, we can do square-circle

since the circle is inscribed in the square, the circle's diameter is 8, so its radius is 4

8²-4²π = 64-16π

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3 years ago

Shane is goin to the movies with his friends.His mom give them $15.00 to spend on snacks. Drinks cost $2.00 each and candy cost

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<h3>- - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - </h3>

➷ Simply divide the values:

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➶ Hope This Helps You!

➶ Good Luck (:

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3 years ago

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3 years ago

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Artyom0805 [142]

Answer:

Range = 115$

Standard Deviation = 43.76$

Variance = 1915.142$

Option A) The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.

Step-by-step explanation:

We are given the data for prices in dollars for one night at different hotels in a certain region.

234, 160, 119, 131, 218, 207, 146, 141

Range:

Sorted data: 119, 131, 141, 146, 160, 207, 218, 234

$\text{Range} = 234-119 = 115\$$

Standard Deviation:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

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$Mean =\displaystyle\frac{1356}{8} = 169.5$

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Variance =

$\sigma^2 = 1915.142\$$

Measure of variance for someone searching for room:

Option A) The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.

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