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3 years ago

6

I Do not know what to do ANYONE help plz

1 answer:

Fudgin [204]3 years ago

8 0

Answer:

for circle in circle: 75π

circle in square: 64-16π

note that answers are in exact form, since I don't know how the answer should be written (exact or decimal etc.)

Step-by-step explanation:

for circle in circle, we see that smaller circle (white circle) has radius 5 and big circle has radius 10. therefore we can find area of shaded area by doing

area of big - area of small

10²π - 5²π = 100π - 25π = 75π

circle in square, applying the same method, we can do square-circle

since the circle is inscribed in the square, the circle's diameter is 8, so its radius is 4

8²-4²π = 64-16π

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pav-90 [236]

Food is $6,750
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7 0

2 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

3 years ago

Solve (x +9)2 = 25.

alexandr1967 [171]

Answer:

$x = - 4 \: or \: x = - 14$

Step-by-step explanation:

We have been given the equation

$(x + 9) {}^{2} = 25$

and we are asked to apply the square root property of equality to our given a equation and isolate the variable

First, take the square root of both sides of our equation

$\sqrt{(x + 9) {}^{2} } = \sqrt{25}$

$x + 9 = \: 15$

$x + 9 = 5 \: or \: x + 9 = - 5$

$x + 9 - 9 = 5 - 9 \: or \: x + 9 - 9 = - 5 - 9$

$x = - 4 \: or \: x = - 14$

<em>THEREFORE, THERE ARE TWO SOLUTIONS FOR OUR GIVEN EQUATION</em>

<em> $x + 9 = 5 \: then \: x = - 4. \\ x + 9 = - 5 \: then \: x = - 14$ </em>

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8 0

2 years ago

Is 8:2 greater than 5:1? <br><br> I need someone to help me clarify if this is correct. Thanks.

kaheart [24]

Answer:

No, 8:2 = 4:1 which is less than 5:1

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

gladu [14]

Answer:sadddddddddddddddddddddddddddddddddddddddddddddddddddd

Step-by-step explanation:

ddddddddddddddddddddddddddddddddddddddddddddddddddddddddd

3 0

2 years ago