Call the point of intersection of the diagonals point X.
Each base is the hypotenuse of an isosceles right triangle whose sides are the diagonals and whose 90° angle is at X. The altitude of that triangle (⊥ distance to the base from X) is half the length of the hypotenuse. Then the height of the trapezoid is half the sum of the base lengths.
The area of the trapezoid is the product of the height and half the sum of the base lengths, hence is the square of half the sum of the base lengths.
... Area = ((16 cm +30 cm)/2)² = (23 cm)² = 529 cm²
The volume of the solid is 540 mm
Step-by-step explanation:
The volume a rectangular prism is calculated as the product of its length, width and height.
Mathematically, V=l*w*h where l is length of the prism, w is width and h is the height
Given that the dimensions of the rectangular prism as;
Length=15 mm
Width= 6 mm
Height = 6 mm
V=15*6*6= <u>540 mm
</u>
<h2>
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Answer:
x + 3 is a factor of the polynomial.
Step-by-step explanation:
We have been given that p(x) is a polynomial with integer coefficient.
Also p(-3)=0
Since, p(-3) =0, hence, we can say that -3 is a zero of the polynomial.
Now, we apply factor theorem.
Factor Theorem: If 'a' is a zero of a function f(x) then (x-a) must be a factor of the function f(x).
Applying this theorem, we can say that (x+3) must be a factor of the polynomial.
Hence, first statement must be true.
Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.
Difficulty with Word Problems
Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:
