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3 years ago

A

Mathematics

1 answer:

valentina_108 [34]3 years ago

3 0

Answer:

Reflect Quadrilateral A over the x-axis. Label the image quadrilateral B. Reflect

Quadrilateral B over the y-axis. Label the image C.

Step-by-step explanation:

You might be interested in

If two fair dice are tossed, what is the smallest number of throws, n, for which the probability of getting at least one double

amid [387]

This is a rather famous probability problem.

The easiest way to solve this is to calculate the probability that you WON'T roll a "double 6" (or a twelve) each time you roll the dice. There are 36 ways in which dice rols can appear and only one is a twelve. So, for one roll, the probability that you will NOT get a twelve is (35/36)^n where 35/36 is about .97222222 and n would equal 1 for the first trial. So for your first roll the odds that you WON'T get a 12 is .97222222.

For the second roll we calculate (35/36) to the second power or (35/36)^2 which equals about .945216.

When we get to the 24th roll we calculate (.97222222)^24 which equals 0.508596.

For the 25th roll, we calculate (.97222222)^25 which equals 0.494468. For the first time we have reached a probability which is lower than 50 per cent. That is to say, after 25 rolls, we have reached a point in which the probability is less than 50 per cent that we will NOT roll a twelve.

To phrase this more clearly, after 25 rolls we reach a point where the probability is greater then 50 per cent that you will roll a 12 at least once.

Please go to this page 1728.com/puzzle3.htm and look at puzzle 48. (The last puzzle on the page). An intersting story associated with this probability problem is that in 1952, a gambler named Fat the Butch bet someone $1,000 that he could roll a 12 after 21 throws. (He miscalculated the odds [as we know you need 25 throws] and after several HOURS, he lost $49,000!!!)

Please go that page and it has a link to the Fat the Butch story.

3 0

4 years ago

Hamburger sells 3 pounds for six dollars if Samantha 510 pounds of hamburger how much will she pay

Lina20 [59]

I believe you meant to say that if Samantha bought 510 pounds of hamburger, how much will she pay?

Now from the information we already have, we know that 3 pounds of hamburger will cost 6 dollars.

The next thing we need to know is how much one pound of hamburger will cost. This will help us calculate how much the rest will cost.

we now form an equation to assist us.
3 = 6
1= x

(where x represents the unknown price of one pound of hamburger)

Now we must cross-multiply:

3 * x = 6 x 1

3x = 6

x = 6/3

x = 2

therefore one pound of hamburger costs 2 dollars.

Now, If one pound costs 2 dollars, how about 510 pounds?

We simply multiply: 510 x 2 = 1,020

Therefore Samantha will pay 1, 020 dollars for 510 pounds of hamburger.

5 0

3 years ago

The Andriomeda galaxy is... times further away from the earth than saturn

Triss [41]

Okay okay thanks for the update I am on my way to get my car

6 0

3 years ago

For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean

ki77a [65]

Answer:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu=?,\sigma=?)$

We are interested on this probability

$P(X>X+3\mu)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

And we can find the following probablity:

$P(Z>3) = 1-P(Z$

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0

3 years ago

Find P(x)=... polynomial

Aneli [31]

Answer: D) P(x) = -23

Step-by-step explanation:

Substitute 2 for x:

1 - 2(2)^2-3(2)^2+4(2)

Exponent

1-2(4)-3(8)+4(2)

Multiply

1-8-24+8

Combine like terms

-23

<em>Hope it helps <3</em>

3 0

3 years ago