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Svetllana [295]
3 years ago
9

Solve for x: y=-3x+6

Mathematics
2 answers:
vazorg [7]3 years ago
8 0
The answer is : x= -y/3+2
Lynna [10]3 years ago
8 0

Answer:

-1/3y + 2  (Negative 1 over 3 plus 2)

Step-by-step explanation:

Step 1: Flip the equation.

−3x+6=y

Step 2: Add -6 to both sides.

−3x+6+−6=y+−6

−3x=y−6

Step 3: Divide both sides by -3.

−3x

−3

=

y−6

−3

x=

−1

3

y+2

Answer:

X= -1/3y + 2

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Please help ill give whoever answers the best the brainliest answer :)))
vodomira [7]

Answer:

w(w-5)

Step-by-step explanation:

Given Width of rectangle = w

Length of rectangle is 5 less than width of rectangle = w - 5

Area of Rectangle = Length x Width = w * w-5 = w(w-5)

8 0
2 years ago
Read 2 more answers
Rana is traveling on an airline that give a maximum weight of 65 kg. the first bag weighs 40.​
n200080 [17]

Answer:

What's the question here?

Step-by-step explanation:

The weight of the 1st bag is independent from the airline weight specification given. If the max weight of 65kg is given, this means that she/he can take on board (including the luggage) a maximum of 65kg. Does not include human weight

6 0
2 years ago
Order from greatest to least:show your work❗️<br><br> 12,-4,8,-3,0
Aneli [31]
The answer would be 12, 8, 0, -3, -4.

The answer is that because 12 is a positive number so that's higher than negative, 8 goes second because its positive and higher than the others, 0 is third because negatives numbers are LOWER than 0, not higher, -3 is next because higher negative numbers are always lower, not greater than smaller numbers because -8 is LOWER than -4 since its on the left of a number line.
6 0
3 years ago
Determine each of the following.
castortr0y [4]

Answer:

(a) \{1,2,3,4,5,6,7,8,9,10\}

(b) 10

(c) \{\}

(d) 0

(e) 1024

Step-by-step explanation:

(a)

A = {x ∈ Z | 0 < x, x² ≤ 100}

We need to find all the elements of given set.

The given conditions are

0                ... (1)

x^2\leq 100

Taking square root on both sides.

-\sqrt{100}\leq x\leq \sqrt{100}

-10\leq x\leq 10             .... (2)

Using (1) and (2) we get

0

Since x ∈ Z,

A=\{1,2,3,4,5,6,7,8,9,10\}

(b)

We need to find the value of  | {x ∈ Z | 0 < x, x² ≤ 100}| or |A|. It means have to find the number of elements in set A.

|A|=10

| {x ∈ Z | 0 < x, x² ≤ 100}| = 10

(c)

B = {x ∈ Z | x > 10, x² ≤ 100}

We need to find all the elements of given set.

The given conditions are

x>10                ... (3)

x^2\leq 100

It means

-10\leq x\leq 10             .... (4)

Inequality (3) and (4) have no common solution, so B is null set or empty set.

B=\{\}

(d)

We need to find the value of |{x ∈ Z | x > 10, x² ≤ 100}| or |B|. It means have to find the number of elements in set B.

|B|=0

|{x ∈ Z | x > 10, x² ≤ 100}| = 0

(e)

We need to find the value of | P(A) |. P(A) is the power set of set A.

Number of elements of a power set is

N=2^n

where, n is the number of elements of set A.

We know that the number of elements of set is 10. So the value of |P(A)| is

|P(A)|=2^{10}

|P(A)|=1024

Therefore |P(A)|=1024.

7 0
2 years ago
1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav
OLga [1]

Answer:

(1) y=C, C\neq0

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant,  C \neq 0, has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

\Rightarrow x=C, where C\neq0.

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0
3 years ago
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