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3 years ago

Solve for x: y=-3x+6

Mathematics

2 answers:

vazorg [7]3 years ago

8 0

The answer is : x= -y/3+2

Lynna [10]3 years ago

8 0

Answer:

-1/3y + 2 (Negative 1 over 3 plus 2)

Step-by-step explanation:

Step 1: Flip the equation.

−3x+6=y

Step 2: Add -6 to both sides.

−3x+6+−6=y+−6

−3x=y−6

Step 3: Divide both sides by -3.

−3x

−3

y−6

−3

−1

y+2

Answer:

X= -1/3y + 2

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6. What are the zeroes for the<br>function<br>f(x) = 2x3 + 12x – 10x2?<br>

agasfer [191]

Answer:

Step-by-step explanation:

f(x) = 2x^3 + 12x – 10x^2 can and should be rewritten in descending powers of x:

f(x) = 2x^3 – 10x^2 + 12x

This, in turn, can be factored into f(x) = x·(x² - 10x + 12).

Setting this last result = to 0 results in f(x) = x·(x² - 10x + 12).

Thus, x = 0 is one root. Two more roots come from x² - 10x + 12 = 0.

Let's "complete the square" to solve this equation.

Rewrite x² - 10x + 12 = 0 as x² - 10x + 12 = 0.

a) Identify the coefficient of the x term. It is -10.

b) take half of this result: -5

c) square this last result: (-5)² = 25.

d) Add this 25 to both sides of x² - 10x + 12 = 0:

x² - 10x + 25 + 12 = 0 + 25

e) rewrite x² - 10x + 25 as the square of a binomial:

(x - 5)² = 13

f) taking the sqrt of both sides: x - 5 = ±√13

g) write out the zeros: x = 5 + √13 and x = 5 - √13.

The three roots are x = 0, x = 5 + √13 and x = 5 - √13.

8 0

3 years ago

Let A be the set of all lines in the plane. Define a relation R on A as follows. For every l1 and l2 in A, l1 R l2 ⇔ l1 is paral

Lyrx [107]

Answer:

Hence, the relation R is a reflexive, symmetric and transitive relation.

Given :

A be the set of all lines in the plane and R is a relation on set A.

$R=\{l_1,l_2\in A|l_1 \;\text{is parallel to}\; l_2\}$

To find :

Which type of relation R on set A.

Explanation :

A relation R on a set A is called reflexive relation if every $a\in A$ then $(a,a)\in R$ .

So, the relation R is a reflexive relation because a line always parallels to itself.

A relation R on a set A is called Symmetric relation if $(a,b)\in R$ then $(b,a)\in R$ for all $a,b\in A$ .

So, the relation R is a symmetric relation because if a line $l_1$ is parallel to the line $l_2$ the always the line $l_2$ is parallel to the line $l_1$ .

A relation R on a set A is called transitive relation if $(a,b)\in R$ and $(b,c)\in R$ then $(a,c)\in R$ for all $a,b,c\in A$ .

So, the relation R is a transitive relation because if a line $l_1$ s parallel to the line $l_2$ and the line $l_2$ is parallel to the line $l_3$ then the always line $l_1$ is parallel to the line $l_3$ .

Therefore the relation R is a reflexive, symmetric and transitive relation.

7 0

3 years ago

5ab^2 - 12a^2b + 3ab + ab^2 + 4a^2b

Agata [3.3K]

Answer:

(a) 6ab² - 8a²b + 3ab

Step-by-step explanation:

Given: 5ab² - 12a²b + 3ab + ab² + 4a²b

In this question, we will be combining like terms.

What are like terms?

Like terms are terms with the same variables and power. For example, 2x and 4x, as well as 2a² and 4a².

Combine like terms:

5ab² - 12a²b + 3ab + ab² + 4a²b

(5ab² + ab²) + (-12a²b + 4a²b) + 3ab

6ab² - 8a²b + 3ab

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2 years ago

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Alex73 [517]

Answer:

Step-by-step explanation:

subract 4 each time

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3 years ago

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antiseptic1488 [7]

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