Answer:
i think it is 5:17
Step-by-step explanation:
length=50
perimeter=170
the highest factor of 50 and 170 is 10 so the answer will be 5:17
hopefully this made sense
Answer:
Step-by-step explanation:
Number of tickets for international flights = 36
Total number of tickets = 95
The probability that a randomly selected airline ticket is for an international flight = 36 / 95 = 0.3789
The probability that a randomly selected airline ticket is for an international flight as a percent rounded to the nearest tenth of a percent = 0.3789 x 100 = 37.9%
% of males surveyed = 0.236 + 0.218 = 0.454 = 45.4%
% of males surveyed who prefer chicken = 0.236 out of 0.454 = 0.236 / 0.454 = 0.5198 = 51.58% = 52.0%
<em>hope this helps~</em>
33.51 X 85% (0.85) = 28.48
First, tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>), so if cos(<em>θ</em>) = 3/5 > 0 and tan(<em>θ</em>) < 0, then it follows that sin(<em>θ</em>) < 0.
Recall the Pythagorean identity:
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
Then
sin(<em>θ</em>) = -√(1 - cos²(<em>θ</em>)) = -4/5
and so
tan(<em>θ</em>) = (-4/5) / (3/5) = -4/3
The remaining trig ratios are just reciprocals of the ones found already:
sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/3
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -5/4
cot(<em>θ</em>) = 1/tan(<em>θ</em>) = -3/4
Answer:
option B.
About 16% of the books have fewer than 150 pages
Step-by-step explanation:
Since we are dealing with a normal distribution
68.27% of the values will fall in the range with the standard deviation
(180-30 , 180+30) = (150, 210)
Approximately 15.86% of the values will be higher than 210
and the rest 15.86% will be lower than 150
So the correct answer is option B.
About 16% of the books have fewer than 150 pages
