Answer:
(221.39, 300.61) and (255.2223, 266.7777)
Step-by-step explanation:
Given that X, the lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days
Middle 98% would lie on either side of the mean with probability ±2.33 in the std normal distribution on either side of 0
Corresponding we have x scores as
Between 
and 
i.e. in the interval = (221.39, 300.61)
If sample size = 47, then std error of sample would be
So 98% of pregnancies would lie between
and 
= (255.2223, 266.7777)
<span>2.8 x 10^6 N
We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that:
F * 35m = 9.8 x 10^7 kg*m^2/s^2
Solving for F, gives
F * 35m = 9.8 x 10^7 kg*m^2/s^2
F = 9.8 x 10^7 kg*m^2/s^2 / 35m
F = 2.8 x 10^6 kg*m/s^2
F = 2.8 x 10^6 N
So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
Answer
x=33
Step-by-step explanation:
since they're both on the same line we must equal them to 180.
18 + x + 4x -3 = 180 (Now you simplify terms)
5x + 15 = 180 (Subtract the 15 from both sides)
5x = 165 (divide by 5 to isolate the variable)
x = 33 (Hope I was able to help :) )
Answer:
See picture above
Explanation:
Hope this helps and have a nice day
