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Alina [70]
3 years ago
14

Find the exact value of cos (1140)°.

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0

now let's recall that a full circle has 360°, so then 1140 = 360 + 360 + 360 + 60.

namely, 1140 is 3 full-go-around the circle and then it lands on the I Quadrant at 60°.  Thus cos(1140°) = cos(60°).

what's that cosine of 60°?  Check the picture below.

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Mai will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $59.96 and costs an a
juin [17]

Answer:

600 miles.

Step-by-step explanation:

So basically we can write both plans as linear functions:

F(x) = $59.96+$0.14 . x

S(x) = $71.96+$0.12 . x

Where F(x) is the first plan, S(x) is the second one and X are the miles driven.

To know how many miles does Mai need to drive for the two plans to cost the same, we equalize both equations and isolate x.

F(x) = S (x)

$59.96+$0.14.x = $71.96+$0.12.x \\0.14x-0.12x=71.96-59.96\\0.02x=12\\x=12 : 0.02\\x= 600

Mai has to drive 600 miles for the two plans to cost the same-

4 0
3 years ago
1 1/2 as a fraction
Alik [6]

Answer:

1.5

Step-by-step explanation:

divide 1/2 and add 1

4 0
3 years ago
In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find: AC, if CD = 6√2 in.
klio [65]

Answer:

AC = 12 units.

Step-by-step explanation:

Δ ACD is right-angled. ( as CD ⊥ AB).

cos 45° = CD / AC = 6√2 / AC

AC = 6√2 / cos 45°

AC = 6√2 / 1 /√2

= 6√2 *√2

= 6 * 2

= 12   (answer)

HOPE THIS HELPED ;3

5 0
3 years ago
Solve x2 - 8x = 3 by completing the square. Which is the solution set
Simora [160]

Answer:

4\pm\sqrt{19}

Step-by-step explanation:

Move everything to left side

x^{2} -8x -3 =0

Now to solve this square equation we need to find Descriminant

D=b^{2} -4ac=64+12=76

As Descriminant D is greater than 0 then we have 2 solutions which we can calculate by this formula

x_{1,2}=\frac{-b\pm\sqrt{D}}{2a} =\frac{8\pm2\sqrt{19}}{2}=4\pm\sqrt{19}

3 0
3 years ago
Need help on writing a proof.
viva [34]

Answer: Congruent


Step-by-step explanation:

Line BC is reflexive to itself

AB is congruent to CD, and that's given

Line AC is congruent to BC, using these prior proofs

Angle EDC and Angle FAB are congruent, and that's a given.

You can conclude that they are congruent by AAS



5 0
3 years ago
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