All categories

3 years ago

Find the exact value of cos (1140)°.

Mathematics

1 answer:

slamgirl [31]3 years ago

8 0

now let's recall that a full circle has 360°, so then 1140 = 360 + 360 + 360 + 60.

namely, 1140 is 3 full-go-around the circle and then it lands on the I Quadrant at 60°. Thus cos(1140°) = cos(60°).

what's that cosine of 60°? Check the picture below.

You might be interested in

The base and height of a rectangle are 134.4 and 98.46, find the sum of the lengths of the two diagonals of the rectangle?

Len [333]

Answer:

232.86

Step-by-step explanation:

134.4

+ 98.46

=232.86

232.86

+232.86

=465.72

Sorry that's all I know po

3 0

2 years ago

Given the image, solve for the problem.

quester [9]

Answer:1.5 hours

Step-by-step explanation:

$8.50 is for 1/2 hour

In $25.50, the can use for (25.5*.5)/8.5 = 1.5 hours

7 0

3 years ago

Read 2 more answers

15•(3 + b) = 45 + b

Alekssandra [29.7K]

Subtract 15 from both sides that gets rid of 15 and your left with 3b =30b divide 3 on both sides and the answer is 10

8 0

2 years ago

Use distributive property to simplify (0.32x+5.3)+(0.5x+5.6)+(0.03x+0.2)

Serhud [2]

the answer is

.85x+11.1

6 0

3 years ago

Read 2 more answers

Find the total surface area of this cone. Round to the nearest tenth.

leva [86]

Step-by-step explanation:

for given cone:

h = 3 ft, r = 3 ft

Let l be the Slant height of cone.

$\therefore \: l = \sqrt{ {h}^{2} + {r}^{2} } \\ = \sqrt{ {3}^{2} + {3}^{2} } \\ = \sqrt{9 + 9} \\ = \sqrt{2 \times 9} \\ \therefore \: l= 3 \sqrt{2} \: ft \\ \\ total \: surface \: area \: of \: cone \\ = \pi \: r(l + r) \\ = 3.14 \times 3(3 \sqrt{2} + 3) \\ = 9.42 \times 3( \sqrt{2} + 1) \\ = 28.26 \times (1.414 + 1) \\ = 28.26 \times 2.414 \\ = 68.21964 \\ \approx \: 68.2 \: {ft}^{2}$

8 0

3 years ago