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3 years ago

Someone please help me ASAP!

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

3 0

Answer:

(x+1, y-3)

Step-by-step explanation:

Because moving x by positive one means that you shift the shape to the right, and subtracting the y by 3 means moving it down by three. I solved it by choosing one point and figuring out how the same point ended up where it is after the translation (I looked at point a and saw how much it moved right and down). Hope this helps! :)

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the sum of one fourth of a number and 17 is equal to the sum of one fifth the number and 18. find the number.

Nikolay [14]

The number is equal to both of them

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3 years ago

Directions: Raise the powers of all variables and numbers indicated, and then turn the following expressions in radical form int

True [87]

The value of the exponents in simple exponential form is $x^{\frac{44}{5}}$ .

The mathematical operation of exponentiation, written as bⁿ, involves the base number (b) and the exponent (or power) number (n). The way to say this word is "b (elevated) to the (power of) n."

Exponentiation corresponds to repeated base multiplication when n is a positive integer since bⁿ is the outcome of multiplying n bases. The exponent is often displayed to the right of the base as a subscript.
The phrase "b to the nth power" or simply "b to the nth" is used to refer to bn. Other variations are "b (raised) to the power of n," "the nth power of b," and "b to the power of n" and "b to the nth power,"

The properties of exponents tell us that when the bases are equal then on multiplication the powers are added and on division the powers are subtracted.

$\sqrt[5]{5^y} \cdot(5^4)^3 = 5^{\frac{y+60}{5} }$

$\sqrt[5]{5^x} \cdot(5^4)^3 = 5^{\frac{x+60}{5} }$

Therefore the properties of exponents can be used to find the exponential solutions.

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5 0

1 year ago

Helpppp ASAP 15 points

Lisa [10]

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Step-by-step explanation:

3 0

3 years ago

Let f(x)=2−|4x−2|. Show that there is no value of c such that f(3)−f(0)=f'(c)(3−0). Why does this not contradict the Mean Value

xenn [34]

Answer:

The mean value theorem is valid if f(x) is continuous in the interval (0,3) and differentiable in the interval (0,3), the problem is that f(x)=2−|4x−2| is not differentiable in x = 1/2 because 4*1/2 - 2 = 0 and the function |x| is not differentiable in x = 0.

f'(x) = (-4)*(4x−2)/|4x−2|

f(3) = 2−|4*3−2| = 8

f(0) = 2−|4*0−2| = 0

Replacing in f'(c) = f(3)−f(0)/(3−0)

(-4)*(4c−2)/|4c−2| = (8 - 0)/3

(-4)*(4c−2)*3/8 = |4c−2|

-3/2*4c + 3/2*2 = |4c−2|

-6c + 3 = |4c−2|

That gives us two options

-6c + 3 = 4c−2

5 = 10c

1/2 = c

6c - 3 = 4c−2

-1 = -2c

1/2 = c

But f'(1/2) is not defined, therefore there is no value of c such that f(3)−f(0)=f'(c)(3−0).

3 0

3 years ago

Prove that angles opposite to equal sides of an isosceles triangle are equal.

ZanzabumX [31]

Answer:

Step-by-step explanation:

Take a triangle ABC, in which AB=AC.

Construct AP bisector of angle A meeting BC at P.

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AP=AP[common]

AB=AC[given]

angle BAP=angle CAP[by construction]

Therefore, ∆ABP congurent ∆ACP[S.A.S]

This implies, angle ABP=angleACP[C.P.C.T]

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3 years ago