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Colt1911 [192]
3 years ago
8

My school is planning a field trip and over and buses and vans for the trip each bus carries up to 60 students requires for chap

erones and cost $1000 to charter a bank turns up to 10 students requires two chaperones and cost $100 for gas at least 300 students plan to attend and 36 parents offered to chaperone find the number vans and buses the school should rent to minimize the cost
Mathematics
1 answer:
diamong [38]3 years ago
8 0
There should end up being 5 buses
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A team has 3 wins for every loss they loss games how many did they win??
OLEGan [10]
The team has lost only 6 games (according to the comments). Let's say "x" is the amount of losses and "y" is the amount of wins.

For every loss, they have 3 wins, so in the end, this would be the equation:
y = 3x
or
y = 3 \times x
Although the first one would be the easier and most understandable to read.

So:
y = 3(6)
would equal
18
5 0
3 years ago
Write the rule of the nth term of each sequence 7,4,1,-2
Zarrin [17]

Answer:

a_{n} = 10 - 3n

Step-by-step explanation:

the terms 7, 4, 1, - 2 form an arithmetic sequence with n th term

a_{n} = a_{1} + (n - 1)d

where d is the common difference and a_{1} the first term

here d = - 2 - 1 = 1 - 4 = 4 - 7 = - 3 and a_{1} = 7, hence

a_{n} = 7 - 3(n - 1) = 7 - 3n + 3 = 10 - 3n


8 0
4 years ago
Simplify. Your answer should contain only positive<br> exponents.<br> -2^х
polet [3.4K]

Answer: I'm not entirely sure, but maybe 1/x^2?

8 0
3 years ago
Four more than six times a number is at least 40. Find the possible range of values.
Setler [38]
1. Let x = #
2. "Five less than six times a number" can be written as: 6x - 5
3. "is at least" is the same as "greater than or equal to" and can be written as: >=
4. "nine subtracted from two times that number" can be written as: 2x - 9
5. the equation is: 6x - 5 >= 2x - 9
6. solve for x by grouping the x variable terms on one side and the constants on the other side:
6x - 5 >= 2x - 9
-2x +5 -2X +5
4x >= -4
7. divide each side by 4, and you get: x = -1
5 0
4 years ago
What are the possible number of positive, negative, and complex zeros of f(x) = x6 – x5– x4 + 4x3 – 12x2 + 12 ?
FinnZ [79.3K]
This is a polynomial with more than 2 as a degree. Using Descartes Rule of Signs: 
f(x) = x⁶ + x⁵ + x⁴ + 4x³ − 12x² + 12 
Signs: + + + + − + 2 sign changes ----> 2 or 0 positive roots 
f(−x) = (−x)⁶ + (−x)⁵ + (−x)⁴ + 4(−x)³ − 12(−x)² + 12 f(−x) = x⁶ − x⁵ + x⁴ − 4x³ − 12x² + 12 
Signs: + − + − − + 4 sign changes ----> 4 or 2 or 0 negative roots 
Complex roots = 0, 2, 4, or 6 
7 0
3 years ago
Read 2 more answers
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