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elixir [45]
3 years ago
10

What is -1/6 times -1/5

Mathematics
1 answer:
zimovet [89]3 years ago
5 0
<h3>Answer:</h3>

\frac{1}{30}

<h3>Explanation:</h3>

Multiply the numerators together. -1*-1=1

Multiply the denominators together. 6*5=30

Put the two products together in a new fraction. \frac{-1}{6}*\frac{-1}{5}=\frac{1}{30}

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Which of the following is the most appropriate unit to describe the rate of the cost of gasoline?
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Please help me to solve all the questions would appreciate it if its with full working
Degger [83]

∠ KGH is equal to 77°. This is arrived at by using the knowledge of the total angles in Parallel Lines.

<h3>What are the total angles on a straight line?</h3>

According to the laws of lines and angles, the total number of angles that can exist on a straight line is 180°.

If ∠CED = 25° and ∠BFL = 78°, then: ∠KGH = 180-(25+78), which is equals 77°. This is because the total angles on a straight-line total 180°

<h3>What is ∠LKJ?</h3>

Recall that in angles in parallel lines:

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  • Interior According always sum up to 180°

Hence,

We can derive ∠LKJ because it is congruent with ∠BGJ.

To get ∠BGJ, we must get ∠LFH because both of them are interior angles and sum up to 180°.

To get ∠LFH, we must subtract ∠BFL from 180° because they are both angles on a straight line.

Hence ∠LFH = 180 - 78 = 102°

Recall that ∠LFH and ∠BGJ are interior angels. Hence

∠BGJ = 180 - 102 = 78°.

Since ∠BGJ is a corresponding ∠ with ∠LKJ, therefore

∠LKJ = 78°

<h3>What is ∠ALM?</h3>

∠ALM is ∠BFL because they are both corresponding angles and are therefore congruent.

<h3>What are the solutions to section B?</h3>

  1. Because ∠ACB and ∠BAC are equal, therefore sides AB and BC are equal in length. We can tell that  ∠ACB and ∠BAC are equal because the total angles in the triangle are equal to 180°

     2. The name given to the triangle mentioned above is Obtuse      

          Triangle. This is because one of the angles exceeds 90°.

Learn more about angles in parallel lines at:
brainly.com/question/24607467
#SPJ1

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