All categories

3 years ago

WILL GIVE BRAINLIST!!!!!!!FACTOR THIS COMPLETELY 4x^2 − 25

Mathematics

1 answer:

Wittaler [7]3 years ago

3 0

Answer:

(2x - 5)(2x +5)

Step-by-step explanation:

4x^2 is a perfect square with a square root of 2x, and 25 is also a perfect square with a square root of 5. The difference of two perfect squares a and b can be written as $(\sqrt{a} - \sqrt{b} )(\sqrt{a} +\sqrt{b} )$ . So, 4x^2 - 25 can be factored into (2x-5)(2x+5).

Hope that helped! ;)

You might be interested in

Simplify the question

zimovet [89]

Answer: 50.4537849152
Hope this helped!

8 0

3 years ago

Read 2 more answers

If it takes Mr. Williams 1/5 hour to grade each of his students’ tests, how many tests can he grade in 4 hours?

MaRussiya [10]

Answer:

1234567891011121314151617181920

7 0

3 years ago

Read 2 more answers

What is two thirds of four fifths?

BabaBlast [244]

Answer:

The word "of" in the question means multiply, so you need to multiple these two fractions.

2/3 x 4/5 = 8/15

8 0

3 years ago

Read 2 more answers

A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min

sesenic [268]

$A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})$
$\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$
$A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4$

We're given that $A(0)=30$ . Multiply both sides by the integrating factor $e^{t/100}$ , then

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C$
$A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}$

Given that $A(0)=30$ , we have

$30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02$

so the amount of salt in the tank at time $t$ is

$A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}$

3 0

3 years ago

50.4 is what percent of 280

shusha [124]

Us the is over of method
50.4•100=5,040
5,040/280=x
X= 18

5 0

3 years ago