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agasfer [191]
3 years ago
15

PLEASE I NEED AN ANSWER ASAP!!

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

The answer is C -3•(-5)=15

The process of elimination would’ve been helpful because two negatives equal a positive and one negative equals a negative, therefore you could get rid of B and D. Also, for answer A the diagram already tells you that each entity is negative, so there should be no positive numbers in the equation (besides from the answer possibly). I hope that made sense.

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16y=14+9y please answer 23 points
NeTakaya

Answer:

<h2>y = 2</h2>

Step-by-step explanation:

16y=14+9y\qquad\text{subtract}\ 9y\ \text{from both sides}\\\\16y-9y=14+9y-9y\\\\7y=14\qquad\text{divide both sides by 7}\\\\\dfrac{7y}{7}=\dfrac{14}{7}\\\\y=2

4 0
3 years ago
I don't get the answer
Goshia [24]
A' is (-12, 6)
B' is (0,6)
C' is (3, -3)
D' is (-9, -3)

Hope this helps!
7 0
3 years ago
Towns X, Y, and Z are on the same straight road. Town Y is between Town X and Town Z. Town X is 57 miles from Town Z, and Town Y
Ray Of Light [21]
The distance between town X and Town Y is equal to the difference between the distance between Town X and Town Z and the distance from Town Y and Town Z. Mathematically
                      d (X-Y) = d (X-Z) - d(Y-Z)
Substituting,
                      d(X-Y) = 57 miles - 28 miles = 29 miles
Thus, the distance from Town X to Town Y is 29 miles. 
6 0
3 years ago
Read 2 more answers
I need help with this ASAP
vodomira [7]

Answer:

Its 0 because thats the only value not bigger than 4

Step-by-step explanation:

3 0
3 years ago
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A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th
morpeh [17]
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
6 0
3 years ago
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