What times what equals 39

1 answer:

5 0

A possible answer could be 13 multiplied by 3, or maybe 39 by 1. I don't really know how to explain how I got my answer, but I hope that this helped you out! :)

You might be interested in

<img src="https://tex.z-dn.net/?f=%28sinx%5E%7B2%7D%20theta%29%5Cfrac%7Bx%7D%7By%7D%281%2Bcostheata%29" id="TexFormula1" title="

beks73 [17]

The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Read more about trigonometry expressions at:

brainly.com/question/8120556

#SPJ1

3 0

2 years ago

Can I have help help on 22,24,26,28,30 please

Dmitriy789 [7]

I'll do 22 for you. 22, 24, 26, 28, and 30, are very similar to each other.

PROPORTIONS:
Draw it out.

5/7 = either c/6, or b/5.
I'll do c/6
5/7 = c/6
solve for c
7c=30
c=30/7
now do the same thing to the remaining side, b.
there!