Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
Answer:
i think it is the last one.
Answer:
1) A=5
Step-by-step explanation:
1) W should be greater than 1, so the only option that satisfies this is A which is 5.
(For the number line please look at the attachment)
I'm sorry, I don't know how to solve the second problem. I hope the first question helps. Sorry and Hope its clear.
145-10x=10x-35
Add 35 to both sides.
175-10x=10x
Add 10x to both sides.
175=20x
Divide both sides by 20
8.75=x
