CAN SOMEONE BE NICE AND HELP ME K THANKS;)
1 answer:
You might be interested in
Hi there! :)
Solve for j(h(x)):
h(x) = x² + 4
j(x) = 4x - 1
Substitute in h(x) into "x":
j(h(x)) = 4(x² + 4) - 1
j(h(x)) = 4x² + 16 - 1
j(h(x)) = 4x² + 15
Solve at x = 2:
4(2)² + 15 = 4(4) + 15 = 31.
No the points have to be on a cross on the x and y axis
Answer:
Problem:
Consider a rectangle such that the length of the rectangle is 12 more than thrice its width. Find a formula for the length in terms of its width. Take width as 'x'.
Step-by-step explanation:
Consider a rectangle such that the length of the rectangle is 12 more than thrice its width. Find a formula for the length in terms of its width.
Let the width be 'x'.
Therefore, as per question, length is 12 more than thrice the width.
Thrice the width means . 12 more means adding 12 to the result.
Therefore, the length of the rectangle is
So, the above question expresses the length of the rectangle as which is the required answer.