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balu736 [363]
3 years ago
8

Write the area A of a square as a function of its perimeter P. ...?

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0
The answer is A = P²/16

The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s  = s²

Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.

Step 1:
P = 4s
s = P/4

Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
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Vesna [10]
<h3>Answer:  9/41</h3>

==========================================================

Explanation:

We have a triangle with these three sides.

  • a = 80
  • b = unknown
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Use the pythagorean theorem to find b

a^2+b^2 = c^2

b = sqrt(c^2 - a^2)

b = sqrt(82^2 - 80^2)

b = sqrt(324)

b = 18

This is the missing vertical leg of the triangle. And this is also the side opposite angle C.

We have enough information to compute the sine of the angle.

sin(angle) = opposite/hypotenuse

sin(C) = AB/AC

sin(C) = 18/82

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sin(C) = 9/41

6 0
3 years ago
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Marizza181 [45]
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tigry1 [53]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
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Masteriza [31]
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Flauer [41]

Answer:

x=-1

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Step-by-step explanation:

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