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balu736 [363]
3 years ago
8

Write the area A of a square as a function of its perimeter P. ...?

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0
The answer is A = P²/16

The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s  = s²

Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.

Step 1:
P = 4s
s = P/4

Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
aleksley [76]

The length of PR is 4.4 units.

Explanation:

It is given that the length of the hypotenuse is 10 units.

Also, the angle of R is 64°

To find the length of PR, we shall use the cosine formula,

\cos \theta=\frac{a d j}{h y p}

Here,  \theta=64, adj = PR and hyp = 10

Substituting these values in the formula, we get,

\cos 64=\frac{P R}{10}

Multiplying both sides by 10, we get,

10*\cos 64={P R}

Substituting the value for cos 64, we get,

10*0.438={P R}

Multiplying, we have,

4.38=PR

Rounding off, we get,

PR=4.4

Thus, the length of PR is 4.4 units.

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1 and 16/24 + 1 and 21/24
AlexFokin [52]

Answer:

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3 and 13/24

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