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balu736 [363]
3 years ago
8

Write the area A of a square as a function of its perimeter P. ...?

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0
The answer is A = P²/16

The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s  = s²

Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.

Step 1:
P = 4s
s = P/4

Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
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ivanzaharov [21]
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3 0
3 years ago
When 9 2/3 is written in simplest radical form, which value remains under the radical?
Vera_Pavlovna [14]

Answer:

The value under the radical is 3

Step-by-step explanation:

9^(2/3) This means 9 squared then find find the cube root of the answer.

9^(2/3)=∛(9^2 )

= ∛81

= ∛(3×3×3×3) = ∛(3)³ ₓ ∛3

= 3∛3

The value under the radical is 3

I hope this now shows clearly the number under the radical is 3.

BRAINLIEST?

3 0
2 years ago
To solve 5(2^x + 4) = 15...
horrorfan [7]

I don't think you need answer for that you already did it.

5 0
2 years ago
Solve the system of equations 5x-2y=88 3x+4y=58 show all work
diamong [38]
The given equations are:

5x - 2y = 88
3x + 4y =  58

Multiplying the 1st equation by 2, we get the new set of equations as:

10x - 4y = 176
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Adding the two equations, we get:

10x - 4y + 3x + 4y = 176 + 58
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x =  18

Using the value of x in 1st equation, we get:

5(18) - 2y = 88
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y = 1

So, the solution of the equation is (18, 1)

6 0
3 years ago
Read 2 more answers
what is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? y = 4x − 2 y = 2x − 4 y = −3(x − 4) y =
Brilliant_brown [7]
Equation in point slope form is given by y - y1 = m(x - x1); where m = (y2 - y1)/(x2 - x1).

y - 0 = (6 - 0)/(2 - 4) (x - 4)
y = 6/-2 (x - 4)
y = -3(x - 4)
7 0
3 years ago
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