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3 years ago

The sum of two numbers is 44 and the difference is 2 What are the numbers

Mathematics

2 answers:

Vlada [557]3 years ago

5 0

Answer:

You can try to write two equation from the question

Call x a number and y the other.

The sum of them is 44: x + y = 44

The difference (substract) is 2: x - y = 2

System:

x+y=44

x-y = 2

You can just sum both equations, as the y disappear:

2x = 46

x =46/ 2 = 23

We replace in the equation:

23 - y = 2

y = 21

And we know the numbers are 21 and 23

Aleks04 [339]3 years ago

4 0

Answer:

21 & 23

Step-by-step explanation:

44 ÷ 2 = 22

The two numbers are going to be close to 22.

21 + 23 = 44

32 - 21 = 2

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What is the true solution to the equation below?

Naddik [55]

Yeeee

assuming your equaiton is
$2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)$

remember some nice log rules
$log_a(b)=c$ translates to $a^c=b$
and
$a^{log_a(b)}=b$
and
$xlog_c(b)=log_c(b^x)$
and
$ln(x)=log_e(x)$
and
$log(a)-log(b)=log(\frac{a}{b})$
and
if $log(a)=log(b)$ then a=b

so

we can simplify a bit of stuff here

the $e^{ln(2x)} \space\ and \space\ the \space\ e^{ln(10x)}$ can be simplified to $2x \space\ and \space\ 10x$

so we gots now

$2ln(2x)-ln(10x)=ln(30)$
$ln((2x)^2)-ln(10x)=ln(30)$
$ln(4x^2)-ln(10x)=ln(30)$
$ln(\frac{4x^2}{10x})=ln(30)$
same base so
$\frac{4x^2}{10x}=30$
$\frac{2x}{5}=30$
times both sides by 5
$2x=150$
divide both sides by 2
$x=75$
answer is x=75

5 0

3 years ago

FAST REPLIES PLEASE I NEED HELP

Nonamiya [84]

Answer:

54 degrees

Step-by-step explanation:

No matter the categorization of a triangle the total degrees present will equal 180. You know that you have a corner that equals 44 degrees and another that is 82 degrees. Add the 44 + 82 degrees to get 126 degrees. After getting the 126 degrees, minus that from the total of 180 to get 54 degrees.

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olga55 [171]

Answer:

<u>Perimeter</u>:

= 58 m (approximate)

= 58.2066 or 58.21 m (exact)

= 208 m² (approximate)

= 210.0006 or 210 m² (exact)

Step-by-step explanation:

Given the following dimensions of a rectangle:

length (L) = $\sqrt{252}$ meters

width (W) = $\sqrt{175}$ meters

The formula for solving the perimeter of a rectangle is:

P = 2(L + W) or 2L + 2W

The formula for solving the area of a rectangle is:

A = L × W

<h2>Approximate Forms:</h2>

In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.

13² = 169

14² = 196

15² = 225

16² = 256

Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width). We can use these values to approximate the perimeter and the area of the rectangle.

P = 2(L + W)

P = 2(13 + 16)

P = 58 m (approximate)

A = L × W

A = 13 × 16

A = 208 m² (approximate)

<h2>Exact Forms:</h2>

L = $\sqrt{252}$ meters = 15.8745 meters

W = $\sqrt{175}$ meters = 13.2288 meters

P = 2(L + W)

P = 2(15.8745 + 13.2288)

P = 2(29.1033)

P = 58.2066 or 58.21 m

A = L × W

A = 15.8745 × 13.2288

A = 210.0006 or 210 m²

8 0

3 years ago