Perimeter of square = 4s perimiter of pentagon= 5s, i guess? its a regular one afterall 4s = P 4 (10) = p 40 = P (40 = 5s)/ 5 8 = s
Sorry I dont know how to answer the second one...
Answer:
x = 20
Step-by-step explanation:
first, you would take all of the angles and add them up to 180
2x+40+100=180
second, we combine like terms
2x+140=180
third, we solve for x
2x+140=180
-140 -140
2x=40
x=20
i hope this helps!
<h2>○=> <u>Correct option</u> :</h2>
Diameter of circle P is the same length as the radius of circle Q.
<h3>○=> <u>Steps to derive correct option</u> :</h3>
Given :
Diameter of circle P = 26 cm
Radius of circle P :
![=\tt \frac{diameter}{2}](https://tex.z-dn.net/?f=%20%3D%5Ctt%20%20%5Cfrac%7Bdiameter%7D%7B2%7D%20)
![= \tt \frac{26}{2}](https://tex.z-dn.net/?f=%20%3D%20%5Ctt%20%5Cfrac%7B26%7D%7B2%7D%20)
![\color{plum} = \tt13 \: cm](https://tex.z-dn.net/?f=%5Ccolor%7Bplum%7D%20%3D%20%5Ctt13%20%5C%3A%20cm)
Thus, radius of circle P = 13 cm
Diameter of circle Q = 52 cm
Radius of circle Q :
![= \tt \frac{diameter}{2}](https://tex.z-dn.net/?f=%20%3D%20%5Ctt%20%5Cfrac%7Bdiameter%7D%7B2%7D%20)
![=\tt \frac{52}{2}](https://tex.z-dn.net/?f=%20%3D%5Ctt%20%20%5Cfrac%7B52%7D%7B2%7D%20)
![\color{plum}= \tt26 \: cm](https://tex.z-dn.net/?f=%20%5Ccolor%7Bplum%7D%3D%20%5Ctt26%20%5C%3A%20cm)
Thus, radius of circle Q = 26 cm
Radius of circle R = 52 cm
Diameter of circle R :
![=\tt radius \times 2](https://tex.z-dn.net/?f=%20%3D%5Ctt%20radius%20%5Ctimes%202)
![=\tt 52 \times 2](https://tex.z-dn.net/?f=%20%3D%5Ctt%2052%20%5Ctimes%202)
![\color{plum} = \tt104 \: cm](https://tex.z-dn.net/?f=%5Ccolor%7Bplum%7D%20%3D%20%5Ctt104%20%5C%3A%20cm)
Thus, the diameter of circle R = 104 cm
☆ Conclusion :
▪︎Diameter of circle P is the same length as the radius of circle Q.
Therefore, the correct option is <em>(C) Diameter of circle P is the same length as the radius of circle Q.</em>
A triangle's sum must add to 180 degrees. If two of the angles, summed, equal 50 degrees, then the vertex angle must equal 130 degrees. So, the vertex angle equals 130 degrees.
Answer:
AAS I just answered this question and I got it right.