Question

Define a function f on a set of real numbers as follows: f(x) = 3x − 1 x , for each real number x ≠ 0 Prove that f is one-to-one. Proof: Let x1 and x2 be any nonzero real numbers such that f(x1) = f(x2). Use the definition of f to rewrite the left-hand side of this equation. (Enter the answer as an expression in x1.) Then use the definition of f to rewrite the right-hand side of f(x1) = f(x2). (Enter the answer as an expression in x2.) Equate the expressions obtained for the left- and right-hand sides of f(x1) = f(x2), and simplify the result completely. The result is the following equation. x1 = Therefore, f is .

Answer 1

Answer with Step-by-step explanation:

We are given that

$f(x)=\frac{3x-1}{x}$

For each real number $x\neq 0$

To prove that f is one -to-one.

Proof:Let $x_1$ and $x_2$ be any nonzero real numbers such that

$f(x_1)=f(x_2)$

By using the definition of f to rewrite the left hand side of this equation

$f(x_1)=\frac{3x_1-1}{x_1}$

Then, by using the definition of f to rewrite the right hand side of this equation  of $f(x_1)=f(x_2)$

$f(x_2)=\frac{3x_2-1}{x_2}$

Equating the expression then we get

$\frac{3x_1-1}{x_1}=\frac{3x_2-1}{x_2}$

$3x_1x_2-x_2=3x_2x_1-x_1$

$3x_1x_2-3x_1x_2+x_1=x_2$

$x_1=x_2$

Therefore, f is one-to-one.