9514 1404 393
Answer:
a) average rate = (total distance)/(total time)
b) Rave = 2·R1·R2/(R1 +R2)
c) cheetah's average rate ≈ 50.91 mph
Step-by-step explanation:
a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...
First leg distance: AB = 70·t1 ⇒ t1 = AB/70
Second leg distance: AB = 40·t2 ⇒ t2 = AB/40
The average rate is the ratio of total distance to total time:
average rate = (AB +AB)/(t1 +t2)
average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)
average rate = 560/11 = 50 10/11 . . . mph
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No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.
b) For two rates over the same distance (as above), the average is their harmonic mean:
average rate = 2r1·r2/(r1+r2)
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c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.
That means you are multipliying 10,000,000 by 280,509,031...
The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st
Step-by-step explanation:
Parallel lines have same slopes and different y-intercepts
To find which equation would graph a line parallel to 3y = x + 5
1. Put the equation in the form of y = mx + c
2. m is the slope of the line and c is the y-intercept
3. Look for the equation which has the same values of m and different
values of c
∵ 3y = x + 5
- Divide each term of the equation by 3 to put the equation in the
form of y = mx + c
∴ y = 
x + 
∴ m =
∴ c =
The first answer:
∵ 3y = x + 1
- Divide each term of the equation by 3
∴ y = x +
∴ m =
∴ c =
∵ The two equations have same slope m =
∵ The two equations have different y-intercepts c =
and c =
∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines
The equation 3y = x + 1 would graph a line parallel to 3y = x + 5
Learn more:
You can learn more about slope of a line in brainly.com/question/12954015
#LearnwithBrainly
Answer:p2+2p−24
Step-by-step explanation:(p+6)(p−4)
=(p+6)(p+−4)
=(p)(p)+(p)(−4)+(6)(p)+(6)(−4)
=p2−4p+6p−24
=p2+2p−24
For problem 2:
The answer would be B) Car A travels more miles per gallon of fuel than Car B.
This is because Car B is shown on the graph to travel the same number of miles as Car A using 16 gallons of fuel, while Car A uses only 4 gallons. Thus, Car A travels further with less fuel.
For problem 3:
Let's write out the equation and try to solve.
5x + 1 = 3x + 7
First, subtract 3x from both sides.
5x - 3x + 1 = 3x - 3x + 7
2x + 1 = 7
Now, subtract one from both sides.
2x + 1 - 1 = 7 - 1
2x = 6
Finally, divide both sides by 2.
2x/2 = 6/2
x = 3
You should only get B) One solution
Hope that helped!
