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DiKsa [7]
4 years ago
14

A bank loaned out ​$16000​, part of it at the rate of 7% per year and the rest at 15% per year. If the interest received in one

year totaled ​$1500​, how much was loaned at 7 % question mark How much of the ​$16000 did the bank loan out at 7 % question mark
Mathematics
1 answer:
IceJOKER [234]4 years ago
5 0

Answer:

  $11,250

Step-by-step explanation:

Normally, when I work "mixture" problems, I like to choose the variable so it represents the amount of the largest contributor. Here, that would be the amount invested at 15%.

Unfortunately, the question asks for the amount invested at 7%. Using a variable to represent that amount means that there will be negative numbers involved. Care must be taken in the arithmetic.

Let x represent the amount invested at 7%. Then 16000-x is the amount invested at 15%. The total interest for one year is ...

  0.07x + 0.15(16000 -x) = 1500 . . . . sum of interest amounts at each rate

  -0.08x +2400 = 1500  . . simplify

  -0.08x = -900 . . . . . . . . subtract 2400

  x = 11250 . . . . . . . . . . . . divide by -0.08

The bank loaned $11,250 at 7%.

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8 subtracted from x is less then or equal to 17
Triss [41]

Answer:

it can be written in eqn form as

x-8=>17

or,x=>25

3 0
3 years ago
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ANSWER FAST MY DUDEZ!<br> What is the value of x in the equation <br> 1.8- 3.7x = 4.2x + 0.3
Inessa [10]

1.8- 3.7x = 4.2x + 0.3

Move 4.2x to the other side

Sign changes from +4.2x to -4.2x

1.8-3.7x-4.2x= 4.2x-4.2x+0.3

1.8-3.7x-4.2x= 0.3

1.8-7.9x= 0.3

Move 1.8 to the other side

Sign changes from +1.8 to -1.8

1.8-1.8-7.9x= 0.3-1.8

-7.9x= 0.3-1.8

-7.9x= -1.5

divide both sides by -7.9

-7.9/-7.9x= -1.5/-7.9

x= 0.18987341

Answer: x= 0.18987341

8 0
4 years ago
What are the points of discontinuity y=(x-5)/x^2-6x+5?
ollegr [7]
y = \frac{x - 5}{x^{2} - 6x + 5}
y = \frac{x - 5}{(x - 1)(x - 5)}
y = \frac{1}{x - 1}

x - 1 = 0
  + 1  + 1
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3 0
3 years ago
6. Mary and Steve each travel 845 miles. Mary drove an average of 5 mph faster than Steve and completed the trip in one hour's l
sattari [20]

Answer:

Steve had an average speed of 62.55 mph while Mary had an average speed of 67.55 mph

Step-by-step explanation:

Here, we want to calculate the average speed of each of the two.

From the question, we are told that Mary drove an average of 5 mph faster than steve.

So, let the average speed of Steve be x mph, this means that the average speed of Mary will be (x + 5) mph

Mathematically;

Time = distance/speed

Time taken by Steve = 845/x hours

Time taken by Mary = 845/(x + 5)

But Mary took an hour less to complete her own trip;

This means that;

if we add one hour to the time spent by Mary, then we will have the time spent by Steve

845/(x + 5) + 1 = 845/x

845/(x + 5) = 845/x -1

845/(x + 5) = (845 - x)/x

Cross multiply;

845(x) = (x + 5)(845-x)

845x = x(845-x) + 5(845-x)

845x = 845x-x^2 + 4225 - 5x

x^2 + 5x - 4225 = 0

We can solve this using the quadratic formula;

x = -b ± √(b^2 - 4ac)/2a

where a = 1 , b = 5 , c = -4225

x = -5 ± √(5^2 - 4(1)(-4225)/2(1)

x = -5 ± √(25 + 16,900)/2

x = -5 ± √(16,925)/2

x = (-5 + 130.1)/2 or (-5-130.1)/2

We ignore the negative side as speed cannot be negative

x = (-5 + 130.1)/2 = 62.548 which is approximately 62.55 mph

So steve’s speed is 62.55 mph while Mary’s speed = 62.55 + 5 = 67.55 mph

6 0
3 years ago
Find the slope and y intercept of the graph of the graph of each equation.
AleksandrR [38]
Solve each equation for y and then the slope is m and y-intercept is b as in:
y = mx+b

So, if you do that, you'll get (remember, this is <em>after</em> solving for y):
1. m = -6, b = -2
2. m = 5, b = -1
3. m = -5/3, b = 5
4. m = 0, b = -1/4
5. m = -1, b = -3
6. m = 3, b = -4
7. m = 1/2, b = -5/2
8. m = 7/2, b = 1

Hope this helps.
7 0
3 years ago
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