Answer:
5.82 mm
Explanation:
length of the track, L = 23 m
Initial temperature, T = 7 °C
final temperature, T' = 30 °C
Coefficient of linear expansion, α = 11 x 10^-6 / °C
Let the increase in length of the track on the hot day is ΔL.
use the formula of the linear expansion
ΔL = L x α x ΔT
ΔL = L x α x (T' - T)
ΔL = 23 x 11 x 10^-6 x (30 - 7)
ΔL = 5.82 x 10^-3 m
ΔL = 5.82 mm
Thus, the increase in the length of the track is 5.82 mm.
In projectile motion we can say initial components of velocity is


now here horizontal motion is uniform motion as there is no force in this direction while in vertical direction due to gravity it will accelerate
so we have


so here we have x and y coordinates are related to each other as it will take same time to move the positions
so here correct options are
<em>Projectile motion is a combination of horizontal and vertical motion.
</em>
<em>The horizontal and vertical motions of a projectile are dependent on each other.</em>
The second one is correct not sure about the first one sorry
From my research, the image supports the question. From the graph given, we can construct the equation of the line using the two-point formula. Using the given value of 601 K, we can solve for the missing value of altitude.
y - y1 = [(y2 - y1)/(x2 - x1)](x- x1)
y - 147.52 = [ (567 - 147.54)/(78.11 - 18.4) ](x - 18.4)
Substituting y = 601 to solve for x:
601 - 147.52 = [ (567 - 147.54)/(78.11 - 18.4) ](x - 18.4<span>)
</span>x = 83
Therefore, the probe's instruments will fail at 83 kilometers.