Answer:
Explanation:
angular acceleration α = 5 rad /s ²
θ = 1/2 α t² , θ is angle of rotation , t is time .
= .5 x 5 x 4²
= 40 rad .
θ = l / r , θ is angle formed , l is length unwound , r is radius o wheel .
l = θ x r
= 40 x .1
= 4 m .
During the parts in the orbit where the moon is farthest away from the earth the tides will be low. Whereas during the parts where the moon is closer to the earth the tides will be higher.
Good Luck!
Please correct me if i'm wrong
Answer:
it increases by a factor 1.07
Explanation:
The peak wavelength of an object is given by Wien's displacement law:
(1)
where
b is the Wien's displacement constant
T is the temperature (in Kelvins) of the object
given the relationship between frequency and wavelength of an electromagnetic wave:

where c is the speed of light, we can rewrite (1) as

So the peak frequency is directly proportional to the temperature in Kelvin.
In this problem, the temperature of the object changes from

to

so the peak frequency changes by a factor

<span>Direct Free Kick
Pass
<span>and Dribbling</span></span>