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3 years ago

1.00 x 100 kg of clear liquid (specific heat

Physics

1 answer:

Gwar [14]3 years ago

7 0

Answer:

No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a ... to change 1 kg of liquid water at the normal boiling point (100ºC at atmospheric pressure) to steam (water vapor).

The melting point of lead is 327.3o C. Assume the final temperature of the system is T. Then the amount of energy released by the lead as it solidifies is. ΔQ = mleadLlead = 0.09 kg*(2.45*104 J/kg) = 2205 J

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A hummingbird flies 1.2 m along a straight path at a height of 3.4 m above the ground. Upon spotting a flower below, the humming

Viefleur [7K]

Answer:1.84

Explanation:

Given

Humming bird travels 1.2 m along a straight line at height of 3.4 m

Now bird drops 1.4 m to hover in front of the flower

So bird net displacement is

displacement $=\sqrt{1.2^2+1.4^2}$

displacement $=\sqrt{3.4}$

=1.84

7 0

3 years ago

Which collects light in a reflecting telescope?

Alecsey [184]

Concave lens. These are used in making the objectives of reflection telescopes

4 0

4 years ago

Read 2 more answers

A U.S. Department of Energy report estimates that over 100 billion kWh/year can be saved in the United States by various energy-

I am Lyosha [343]

Answer:

(a). 12 plants

(b). 3171 $

Explanation:

(a)first convert units of 100 billion kWh/year into Watts(W)

also convert the units of 1000 MW into Watts(W)

1 billion = 10^9

1 year = 365*24 = 8760 hrs

100 billion kWh/year = 1 $\frac{100*(10^9)*(10^3)}{8760}$

= $1.142*10^{10}$ W

1000 MW = $1000*10^{6} = 10^{9}W$

no. of plants = $\frac{1.14155*10^{10} }{10^9}$ = 11.4

So 12 plants required

(b)

savings = unit price*total units

= $0.1 * 1.142*10^{10}( \frac{1}{1000*3600} )$

= 3170.9 =3171 $

4 0

3 years ago

Read 2 more answers

A swimmer swims 1000 m in the pool in 8.6 minutes. What was the average speed of the swimmer in m/s?

lawyer [7]

Speed = (distance covered) / (time to cover the distance)

Speed = (1,000 meters / 8.6 minutes) x (1 minute / 60 seconds) = 1.94 m/s
(rounded)

6 0

3 years ago

Read 2 more answers

Receiver maxima problem. When the receiver moves through one cycle, how many maxima of the standing wave pattern does the receiv

shusha [124]

Answer:

Two.

Explanation:

A standing wave or stationary wave are the type of wave in which it oscillates with time but the amplitude does not move.

One complete wave consists of two loops.
It means that when the receiver moves through one cycle, two maxima of standing wave pattern the receiver pass through.

8 0

3 years ago