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3 years ago

A rotation turns a figure about a fixed point called the

Mathematics

1 answer:

labwork [276]3 years ago

3 0

Center of rotation !!!

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Help................

Rina8888 [55]

Answer: DB is 5

Step-by-step explanation:

Alright, lets get started.

Since given that AD is parallel to CB.

And AB is parallel to CD.

And the angle A is given as 90°

It means the given figure is a rectangle.

And the diagonals of the rectangle are equal to each other.

So, $DB=AC$

So, $DB=5$

Hence the answer is 5 ... Answer

Hope it will help :)

4 0

3 years ago

The linear equation y=2x represents the cost y for x pounds of apples.Which ordered pair lies on the graph of the equation?

Yuri [45]

Answer:(1,2), (2,4), (3,6), and alot more here is the graph so you can see!

Step-by-step explanation: hope this helps have a great day!

8 0

3 years ago

Mutually exclusive..

mrs_skeptik [129]

Answer:

there are no answer choices

Step-by-step explanation:

sorry can't help

8 0

3 years ago

Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

3 0

3 years ago

Please help me figure out what x is

ivolga24 [154]

Answer:

the answer is 58 your welcome

8 0

3 years ago