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3241004551 [841]
3 years ago
9

Triangle XYZ is translated 4 units up and 3 units left to yield ΔXYZ. What is the distance between any two corresponding points

on ΔXYZ and ΔXYZ′? A. 25 units B. 7 units C. 5 units D. units

Mathematics
2 answers:
Monica [59]3 years ago
5 0

Look at the picture.

Use the Pythagorean theorem:

d^2=3^2+4^2\\\\d^2=9+16\\\\d^2=25\to d=\sqrt{25}\\\\\boxed{d=5\ units}\to\boxed{C.}

Semmy [17]3 years ago
3 0

Answer:

C.  

5 units

Step-by-step explanation:

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Without
aivan3 [116]

Answer:

Thousandths place.

Step-by-step explanation:

The answer doesn't change that drastically

6 0
2 years ago
Thirteen equals one plus four s
victus00 [196]
13=1+4s
So you find S
So you take out 1, and subtract 1 from thirteen
12=4s so then you divide it by 4
12÷4=3
s=3
6 0
3 years ago
Anyone mind helping me out?
Igoryamba

Answer:

611 square miles

Step-by-step explanation:

Area of triangle = (1/2)*a*b*sinC (formula when u are not given the height of the triangle, but u are given with the angle.)

= (1/2)*30*47*sin(60°)

= 610.54 square miles (2 d.p)

≈611 square miles (rounded to nearest mile)

:)

4 0
2 years ago
5x + 6y = 20 , 8x - 6y = -46
serg [7]

Answer:

5x + 6y = 20_____(1)

8x - 6y = -46_____(2)

Solving simultaneously:

Eqn(1) + Eqn(2)

5x + 8x + 6y + (-6y) = 20 + (-46)

13x = -26

x = -2

substituting this into Eqn (1):

5(-2) + 6y = 20

-10 + 6y = 20

6y = 30

y = 5

hence:

x = -2,y = 5.

7 0
3 years ago
A 2 kg metal cylinder is supplied with 1600J of energy to heat it from 5°C to 13°C. What is the specific heat capacity of the me
Neporo4naja [7]

Answer:

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

Step-by-step explanation:

According to the First Law of Thermodynamics, the heat received by the metal cylinder is equal to the change in the internal energy. That is:

Q = \Delta U

Q = m \cdot c \cdot \Delta T

The specific heat is clear in the previous expression and finally computed:

c = \frac{Q}{m\cdot \Delta T}

c = \frac{1600\,J}{(2\,kg)\cdot (13^{\circ}C-5^{\circ}C)}

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

6 0
3 years ago
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