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Maurinko [17]
3 years ago
12

Solve the indicated variable 2(3n+4)=5n+8

Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0
N=0 is the answer for this problem
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Billy did a survey to answer the following question:
kogti [31]

Answer:

7.8

Step-by-step explanation:

Since the average is 7.8 and everyone scored the same score so

that means everyone scored a 7.8

4 0
3 years ago
8000$ is invested in an account the yields 6% interest per year. After how many years will the account worth 13709.60$ if the in
ozzi

Answer:

After 9 years the account will be worth 13709.60$

Step-by-step explanation:

We are given the following in the question:

We are given the following in the question:

P = $8000

r = 6% = 0.046

n = 12

The compound interest is given by:

A = p\bigg(1+\dfrac{r}{n}\bigg)^{nt}

where A is the amount, p is the principal, r is the interest rate, t is the time in years.

Putting the values, we get,

13709.60 = 8000\bigg(1+\dfrac{0.06}{12}\bigg)^{12t}\\\\\dfrac{13709.60}{8000} = \bigg(1+\dfrac{0.06}{12}\bigg)^{12t}\\\\\Rightarrow 1.7137 = (1.005)^{12t}\\\Rightarrow t \approx 9

Thus, after 9 years the account will be worth 13709.60$

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME, EASY MATH QUESTION !!!! (no links), beainliest xtra points profile thanks, thanks, 5star rating ((IF CORRECT))
Keith_Richards [23]

Answer:

1) A) Increases

2) C) Stays the same

Step-by-step explanation:

1) A) Increases (94 to 95)

2) C) Stays the same (95)

8 0
2 years ago
Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(
Fantom [35]

Answer:

Step-by-step explanation:

3 0
2 years ago
I NEED HELP PLEASEE
xenn [34]

\bf \cfrac{1+cot^2(\theta )}{1+csc(\theta )}=\cfrac{1}{sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\implies \cfrac{1+\frac{cos^2(\theta )}{sin^2(\theta )}}{1+\frac{1}{sin(\theta )}}\implies \cfrac{~~\frac{sin^2(\theta )+cos^2(\theta )}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}\implies \cfrac{~~\frac{1}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}

\bf \cfrac{1}{\underset{sin(\theta )}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}\cdot \cfrac{~~\begin{matrix} sin(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{sin(\theta )+1}\implies \cfrac{1}{sin^2(\theta )+sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\ne \cfrac{1}{sin(\theta )}~\hfill

5 0
3 years ago
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