Center (-15,11) radius 2
1 answer:
Answer:
Step-by-step explanation:
<u><em>The question is</em></u>
How do you write an equation for a circle with center (-15,11) and radius 2?
we know that
The equation of a circle in center radius form is given by
where
(h,k) is the center of the circle
r is the radius of the circle
substitute the given vales
You might be interested in
we know that
The x-intercept is the value of the variable x when the value of the function is equal to zero
so
In the table we have
is a x-intercept, because
For the value of the function is equal to zero
is a x-intercept, because
For the value of the function is equal to zero
therefore
<u>the answer is</u>
the continuous function in the table has two x-intercepts
<h3>Answer:</h3>
Factor 6 from the first two terms.
<h3>Step-by-step explanation:</h3>By factoring out "a", you can better see what "h" needs to be.
- y = 6(x^2 +3x) +14 . . . . 6 factored from first 2 terms
- add the square of half the x-coefficient inside parentheses; add the opposite outside: y = 6(x^2 +3x +2.25) +14 -6(2.25)
- rewrite as a square; combine the constants: y = 6(x+1.5)^2 +0.5