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MAVERICK [17]
3 years ago
11

Center (-15,11) radius 2

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

(x+15)^2+(y-11)^2=4

Step-by-step explanation:

<u><em>The question is</em></u>

How do you write an equation for a circle with center (-15,11) and radius 2?

we know that

The equation of a circle in center radius form is given by

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center of the circle

r is the radius of the circle

substitute the given vales

(x+15)^2+(y-11)^2=2^2

(x+15)^2+(y-11)^2=4

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Help its geometry...............
Digiron [165]

m GH = 57''

________


tan 39° = opposite / adjacent

tan 39° = m GH / m HJ

tan 39° *  m HJ = m GH

m HJ = m GH / tan 39°

m HJ ≈ 57'' / 0.810

m HJ ≈ 70.4''    <——<span>—    measure of the segment HJ</span>

________


sin 39° = opposite / hypotenuse

sin 39° = m GH / m GJ

sin 39° * m GJ = m GH

m GJ = m GH / sin 39°

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m GJ ≈ 90.6''    <———    measure of the segment GJ

________


So the perimeter is

p  =  m GH  +  m HJ  +  m GJ

p  =  57''  +  70.4''  +  90.6''

p  =  218''    <——<span>—    this is the answer.</span>


I hope this helps. =)


Tags:  <em>perimeter right triangle sine cosine tangent sin cos tan trig trigonometry geometry</em>

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The smallest angle in a triangle measures 9 degrees less than the middle angle. The largest angle is 26 degrees more than 3 time
xeze [42]

Answer:

Step-by-step explanation:

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