The following phenotypic classes reflect offspring that were generated as a result of a crossover event
- miniature wings
- garnet eyes
Explanation:
When the miniature wings and garnet eyes links up with the 8 map unit that are present between them. After that the presence of two recombinant classes must complement together and make 8% of total i.e. they contribute 4% each. together the parental classes make up to 92% by contributing 46% one.
This can be understood through a phenotypic ratio calculation, which can be expected from it.
wild type: 4% x 800 = 32
miniature wings: 46% x 800 = 368
garnet eyes: 46% x 800 = 368
miniature wings, garnet eyes: 4% x 800 = 368
The provided question has marked options incorrectely the correct order as follows:
A) Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.
B) Measure the amount of post-translational processing that occurs in the putative DNA repair mutant plants.
C) Measure the somatic mutation rates for the putative DNA repair mutant plants.
D) Expose the putative DNA repair mutant plants to a deaminating agent and select those that have a decreased mutation rate.
E) Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Answer:
The correct answer is: A), C) and E)
Explanation:
The breeder wants to isolate the mutants in tomatoes that are defective in DNA repair, to identify such plants breeder should follow these methods as they will allow best to identifying the defective tomatoes-
Measure the somatic mutation rates for the putative DNA repair mutant plants.
Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants. This will allow the breeder to see and analyze the ability of DNA repair in tomatoes
I believe it would be a fossil of a reptile but I'm not a 100% sure about it.
Answer:
It is fascinating to observe two distinct characters presented by the same plant. The inheritance of this plant can be determined easily by crossing the pure violets exhibiting yellow petals with dark brown marking and erect stems with violets exhibiting no markings, white petals, and prostate stems.
The F1 progeny will originate as a hybrid of the two characters. These F1 plants will then be crossed between themselves and the F2 progeny would be clearly evaluated. If the F2 plants come in the phenotypic ratio of 3: 1, then it would indicate the pleiotropic effect of the alleles found in a single locus. If any other combinations arise post crossing, it would indicate that the non-wild type phenotype is because of many distinct mutant genes.
