For the case of a line through
(
2
,
7
)
and
(
1
,
−
4
)
we have
slope
m
=
Δ
y
Δ
x
=
−
4
−
7
1
−
2
=
−
11
−
1
=
11
Using the point
(
2
,
7
)
we can write the equation of the line in point slope form as:
y
−
7
=
m
(
x
−
2
)
where the slope
m
=
11
.
That is:
y
−
7
=
11
(
x
−
2
)
To get point intercept form, first expand the right hand side so...
y
−
7
=
11
x
−
(
11
⋅
2
)
=
11
x
−
22
Then add
7
to both sides to get:
y
=
11
x
−
15
=
11
x
+
(
−
15
)
This is point intercept (
y
=
m
x
+
c
) form with slope
m
=
11
and intercept
c
=
−
15
.
29/5 should be the correct answer
Start by using trig to find the length of the line LJ
The triangle KJL (big right angled triangle) has been given the following dimensions
Hypotenuse =

The adjacent angle is 30 degrees
Since we have the hypotenuse and the angle we must use the equation
opposite = Sin(angle) x Hypotenuse
Opposite= sin30 x

Opposite=

Therefore line LJ is

Now look at the smaller right angled triangle (LMJ)
Hypotenuse is the line LJ which is

The adjacent angle is 45
Since we have hypotenuse and angle we must use the equation opposite = sin(angle) * h
therefore
x=

* sin45= 4
Answer:
1. -x²-15x-1
2. -33x⁷+10x⁶-14x⁵+4x⁴+11x²-5x+32
Step-by-step explanation:
-20x^2+5x+17 - (-19x^2+20x+18)
-20x² + 19x² + 5x - 20x + 17 - 18
-x² - 15x - 1
-20x^7+10x^6-5x+15 - (13x^7+14x^5-4x^4-11x^2-17)
-20x⁷ - 13x⁷ + 10x⁶ - 14x⁵ + 4x⁴ + 11x² - 5x + 15 + 17
-33x⁷ + 10x⁶ - 14x⁵ + 4x⁴ + 11x² - 5x + 32