(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
I’m not sure but i really really really like points!!!!
Answer: See below
Step-by-step explanation:
number of yellow pieces/number of blue pieces
= 14/24
= 7/12 --> 7 to 12 --> 7:12
The ratio that represents the number of yellow pieces to the total number of pieces is part-to-whole
number of yellow pieces/total number of pieces
= 14/100
= 7/50 --> 7 to 50 --> 7:50
The ratio that represents the number of blue pieces to the total number of pieces is part-to-whole
= 24/100
= 6/25 --> 6 to 25 --> 6:25
It would be subtraction I think
Answer:
$ 1.725
Step-by-step explanation:
4 Pack of coffee = $ 6.90
1 Pack of coffee = $ 6.90 / 4 = $ 1.725
( The word per means " 1 " )
