Ask question

Ask question

All categories

sleet_krkn [62]

3 years ago

12

A Stegosaurus eats six and two fifths big leaves for breakfast and three and one fifth big leaves for lunch. How many leaves did

the Stegosaurus eat in all?

2 answers:

Mkey [24]3 years ago

7 0

Answer:

9 and 3/5

Step-by-step explanation:

Nine and Three Fifths

kow [346]3 years ago

3 0

The answer is 9 3/5.

You might be interested in

A triangle has angles measuring 25° and 45°. What is the measure of the triangle's third angle?

Studentka2010 [4]

Answer:

The answer to this question is B

8 0

3 years ago

Read 2 more answers

Give the numerical value of the parameter p in the following binomial distribution scenarioA softball pitcher has a 0.721 probab

Igoryamba

Answer:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19)$

$P(X=16)=(19C16)(0.721)^{16} (1-0.721)^{19-16}=0.112$

$P(X=17)=(19C17)(0.721)^{17} (1-0.721)^{19-17}=0.051$

$P(X=18)=(19C18)(0.721)^{18} (1-0.721)^{19-18}=0.015$

$P(X=19)=(19C19)(0.721)^{19} (1-0.721)^{19-19}=0.002$

And replacing we got:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19) =0.112+0.051+0.015+0.002= 0.1801$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

For this case our random variable is given by:

$X \sim Binom(n = 19, p = 0.721)$

For this case we want this probability:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19)$

$P(X=16)=(19C16)(0.721)^{16} (1-0.721)^{19-16}=0.112$

$P(X=17)=(19C17)(0.721)^{17} (1-0.721)^{19-17}=0.051$

$P(X=18)=(19C18)(0.721)^{18} (1-0.721)^{19-18}=0.015$

$P(X=19)=(19C19)(0.721)^{19} (1-0.721)^{19-19}=0.002$

And replacing we got:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19) =0.112+0.051+0.015+0.002= 0.1801$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

3 0

3 years ago

What kind of triangle is this?<br> 54°<br> 95°<br> 31°<br> acute<br> right<br> obtuse

seropon [69]

54° is acute

95° is obtuse

31° is acute

6 0

3 years ago

Read 2 more answers

Find the total surface area of the net below:

s2008m [1.1K]

Answer:

57.6

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Elise pays $21.75 for 5 student tickets to the fair.What is the cost of each student ticket

Oduvanchick [21]

Divide 21.75 by 5 students which would mean each students ticket was $4.35.

6 0

3 years ago

Read 2 more answers