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3 years ago

Solve the inequality Need help quick

Mathematics

1 answer:

Alecsey [184]3 years ago

4 0

Answer:

x>1

Step-by-step explanation:

move the constant to the right side and change its sign 7x>10-3

Then subtract the numbers 7x>7

Then divide the inequality by 7 from for both sides.

x>1

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Which fraction is equivalent to 15/30<br> A 3/4<br> B 2/4<br> C 3/5<br> D 5/6

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Answer:

2/4

Step-by-step explanation:

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3 years ago

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Please answer the question from the attachment.

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We have to calculate the pizza´s area.
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3 years ago

What integer would represent 25 feet above sea level?

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Answer:

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Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)

andrezito [222]

Answer:

a) $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325$

b) The lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

Step-by-step explanation:

a) To simplify the expression $\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)$ you must:

Apply Difference of Two Squares Formula: $\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=18,\:b=\tan \left(x\right)$

$\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)$

$324-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Apply the Pythagorean Identity $1+\tan ^2\left(x\right)=\sec ^2\left(x\right)$

From the Pythagorean Identity, we know that $1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)$

Therefore,

$324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325$

b) According with the below graph, the lowest point of $y=\cos \left(x\right)$ , $0\leq x\leq 2\pi$ is when x = $\pi$

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3 years ago

8.42 Three bags of jelly beans contain 26,28 , and 30 beans. In each bag, the percent of the beans that are yellow is 50%, 25%,

olasank [31]

Answer:

Step-by-step explanation:

Figure out the number of yellow beans in each bag:

Bag A: 0.5*26 = 13 beans

Bag B: 0.25*28 = 7 beans

Bag C: 0.2*30 = 6 beans

The total number of beans in the bowl: 26+28+30 = 84

Total number of yellow beans: 13+7+6 = 26

Percentage of yellow beans: 26/84 *100 = 30.9523

Rounded answer: 31%

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2 years ago

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