The ratio of the measures of the sides of a triangle is 8: 15: 17, and its perimeter is 480 in.. Find the measure of the shortes
1 answer:
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Answer:
Step-by-step explanation:
Given
Required
Determine the difference
Represent this with d.
d is calculated using
The equation becomes
Answer:
A maximum of 112 number of 100 - kilograms can be loaded in the container.
Step-by-step explanation:
Given that:
Weight of each crate = 100 kg
The greatest weight that can be loaded in the container = 24000 kg
Weight already loaded in the container = 12800 kg
To find:
The inequality to determine the value i.e. number of 100 - kilograms that can be loaded in the shipping container?
Solution:
Weight already loaded = 12800 kg
Let the number of 100 - kilograms that can be loaded in the container =
Weight of = 100
kg
This combined weight nor be greater than the capacity of the container.
OR we can say, it must be lesser than or equal to greatest weight that can be loaded into the container.
i.e. a maximum of <em>112</em> number of 100 - kilograms can be loaded in the container.
Answer:
a) 0.0256 = 2.56% probability of 4 heads.
0.1296 = 12.96% probability of 4 tails.
b) The probability is 0.0576 = 5.76%.
c) 6 outcomes given 2 heads in 4 tosses. 0.3456 = 34.56% probability of 2 heads in 4 tosses
Step-by-step explanation:
For each throw, we have these following probabilities:
0.4 = 40% probability of heads.
0.6 = 60% probability of tails.
(a) Compare the probability of 4 heads in 4 tosses and 4 tails in 4 tosses.
4 heads:
4 throws, each with 0.4 probability of heads. So
0.0256 = 2.56% probability of 4 heads.
4 tails:
4 throws, each with 0.6 probability of tails. So
0.1296 = 12.96% probability of 4 tails.
(b) Determine the probability of H T H T in 4 tosses.
H = 0.4, T = 0.6. So
The probability is 0.0576 = 5.76%.
(c) Determine the number of outcomes that give us 2 heads in 4 tosses in any order. What is the probability of 2 heads in 4 tosses (use (b) and the number of outcomes)
Number of outcomes:
The possible outcomes are:
H - H - T - T
H - T - H - T
H - T - T - H
T - H - H - T
T - H - T - H
T - T - H - H
6 outcomes given 2 heads in 4 tosses.
Each with probability 0.0576, as found in b)
6*0.0576 = 0.3456
0.3456 = 34.56% probability of 2 heads in 4 tosses