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jeka57 [31]
3 years ago
11

(x − 6)2 − 10 = −7 solve using the square root property

Mathematics
1 answer:
inn [45]3 years ago
4 0

Answer:

x1 = +√3 + 6

x2 = -√3 + 6

Step-by-step explanation:

To solve this equation, using the square root property, you need to understand first this property before you try to solve the value of x

This method is generally used on equations that have the form

ax2 = c   or   (ax + b)2 = c, This last one is our case.    

Now, to solve the equation, you need to isolate the term that contains the squared variable. You can then take the square root of both sides and solve for the variable.  

You shouldn Note that there is always the possibility of two roots for every square root: one positive and one negative. In these cases, you should  Place a  ± sign in front of the side containing the constant after you take the square root, and this, will ensure that the final answer will include both possible roots.

Now that we know the property, let's see how to solve this problem:

(x - 6)^2 - 10 = -7

Let's pass the -10 to the right side

(x - 6)^2 = -7 + 10

(x - 6)^2 = 3

Now we have an expression that looks like (ax + b)^2 = c, so, let's take the square root both sides of the equation:

√(x - 6)^2 = √3

x - 6 = √3

x = ±√3 + 6

Finally, as I stated before, we should put the + and - signs because we have two possibilities, so the two possible values for x would be:

x1 = +√3 + 6

x2 = -√3 + 6

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Olivia lives in a house that is 9 meters below sea level. Olivia goes to school every day, which is 5 meters above sea level how
zhenek [66]

Answer:

I wanna say the answer is 14

Step-by-step explanation:

The answer would be 14 because you are going from -9 to 5 which you just take the difference between the two numbers and the difference is 14.

Hope it helps!

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%20%5Cdiv%20153%20%3D%20" id="TexFormula1" title="3 \div 153 = " alt="3 \div 153 = " align="a
beks73 [17]

If you're looking for the simplified version of the fraction, you have to factor both numerator and denominator.

The numerator is actually already a prime number, so we're good

The denominator factors as 153 = 3^2\cdot 17

So, a 3 appears in both numerator and denominator. We can simplify it:

\cfrac{3}{153} = \cfrac{3}{3^2\cdot 17} = \cfrac{1}{3\cdot 17} = \cfrac{1}{51}

If you want to compute the approximated value of this fraction, simply plug these values into some calculator to get

\cfrac{1}{51} \approx 0.0196078431372\ldots

5 0
4 years ago
Read 2 more answers
An arc that lies between the two sides of a central angle is called a
Harman [31]

Answer:

The answer to this question would be a Minor arc.

Step-by-step explanation:

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3 years ago
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In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot.
Pie

9514 1404 393

Answer:

  69.5

Step-by-step explanation:

The useful trig relation in this case is ...

  Cos = Adjacent/Hypotenuse

  cos(43°) = x/95

  x = 95×cos(43°) ≈ 69.5 . . . . feet

3 0
3 years ago
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A consumer products company found that 42​% of successful products also received favorable results from test market​ research, w
blagie [28]

Answer:

(1) The probability of a successful product given the product is favorable is 0.7778.

(2) The probability of a successful product given the product is unfavorable is 0.2391.

(3) The probability of a unsuccessful product given the product is favorable is 0.2222.

(4) The probability of a unsuccessful product given the product is favorable is 0.7609.

Step-by-step explanation:

Denote the events as follows:

<em>S</em> = a product is successful.

<em>F</em> = a product is favorable.

The information provided is:

P(S\cap F)=0.42\\P(S\cap F^{c})=0.11\\P(S^{c}\cap F)=0.12\\P(S^{c}\cap F^{c})=0.35\\

The law of total probability states that:

P(A)=P(A\cap B)+P(A\cap B^{c})

Use the law of total probability to compute the probability of a favorable product as follows:

P(F)=P(S\cap F)+P(S^{c}\cap F)\\=0.42+0.12\\=0.54

The probability of a favorable product is 0.54.

The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(A\cap B)}{P(B)}

(1)

Compute the value of P (S|F) as follows:

P(S|F)=\frac{P(S\cap F)}{P(F)}=\frac{0.42}{0.54}=0.7778

Thus, the probability of a successful product given the product is favorable is 0.7778.

(2)

Compute the value of P(S|F^{c}) as follows:

P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}=\frac{0.11}{(1-0.54)}=0.2391

Thus, the probability of a successful product given the product is unfavorable is 0.2391.

(3)

Compute the value of P (S^{c}|F) as follows:

P (S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F)}=\frac{0.12}{0.54}=0.2222

Thus, the probability of a unsuccessful product given the product is favorable is 0.2222.

(4)

Compute the value of P (S^{c}|F^{c}) as follows:

P (S^{c}|F)=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}=\frac{0.35}{(1-0.54)}=0.7609

Thus, the probability of a unsuccessful product given the product is favorable is 0.7609.

8 0
4 years ago
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