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Tcecarenko [31]
2 years ago
5

Please can someone help me

Mathematics
1 answer:
DedPeter [7]2 years ago
8 0

Answer:

.7%

Step-by-step explanation:

hope this helps and have a great day :)

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No fakes please!<br> Ill give brainliest!!!
Andreas93 [3]

Step-by-step explanation:

1. 5/8 = 62.5%

2. 1/5 = 20%

3. 4 2/3 = 4.66%

8 0
2 years ago
1. If a polynomial of Degree 4 has an imaginary zero at -2i and a real zero at 5, how many imaginary zeros does it have?
Vadim26 [7]

Answer:

Complex roots for polynomials equations will always come in conjugate pairs.  Since 1-2i is a root, 1+2i will also be a root.  (Just switch the sign of the imaginary part to its opposite.)

Step-by-step explanation:

So far we have 1-2i and 1+2i as roots.  We need two more to make a 4th degree polynomial.

x=1 with multiplicity of 2 means that we count the root twice when we write down the polynomial: (x - 1)(x - 1) = (x - 1)2

Putting it all together, we can construct our polynomial of degree 4 as

y = f(x) = (x - 1)(x - 1)[x - (1-2i)][x - (1+2i)]

Multiply the factors (FOIL):

[x - (1-2i)][x - (1+2i)] =

x2 - (1+2i)x - (1-2i)x + (1-2i)(1+2i) =

x2 - x - 2ix - x + 2ix + (1 + 2i - 2i + 4) =

x2 - 2x + 5

(x - 1)(x - 1) = x2 - x - x + 1 = x2 - 2x + 1

Now multiply the two underlined expressions:

y = (x2 - 2x + 5)(x2 - 2x + 1)

= x4 - 2x3 + 5x2 - 2x3 + 4x2 - 10x + x2 - 2x + 5  by multiplying term by term

= x4 - 4x3 + 10x2 -12x + 5 by collecting like terms.

4 0
2 years ago
Write an appropriate inverse variation equation if y = 9 when x = 3.
pav-90 [236]
\bf \qquad \qquad \textit{direct proportional variation}\\\\&#10;\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;y=9\\&#10;x=3&#10;\end{cases}\implies 9=k3\implies \cfrac{9}{3}=k\implies \boxed{3=k}&#10;\\\\\\&#10;thus\qquad y=3x
3 0
3 years ago
Find three consecutive numbers whose sum is 84
mrs_skeptik [129]

Answer:

27 28 29

Step-by-step explanation:

Let the first be n , and if they are consecutive then the next two numbers are n+1 and n+2.

n+(n+1)+(n+2)=84.

3n+3=84.

⇒3n=81.

⇒n=27.

Hence numbers are n,n+1,n+2→27,28 and 29

3 0
1 year ago
CAN YOU GUYS HELP PLSS
Verdich [7]

Answer:

200

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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