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Colt1911 [192]
3 years ago
11

In each of the cases shown in the figure, the block has been displaced by the same amount from equilibrium. Rank the cases based

on the elastic potential energy stored in the springs.

Physics
2 answers:
garik1379 [7]3 years ago
7 0
Springs in series will experience the same force all throughout and the elongation will add up. Springs in parallel will experience different forces and the elongation will be the same for each. The ranking will be from lowest to highest:
Case 3
Case 2
Case 1
Case 4
Case 5
PolarNik [594]3 years ago
4 0

Answer:

case4 > case 2 > case 5 > case 3 >case 1

Explanation:

if displacement is same for all, then potential energy PE depends on k

<u>case 1) </u>

K1 = k * 2k / (k+2k) =2k/3  (due to series combination of them)

<u>case 2) </u>

K2 =k+k =2k  9 (due to parallel combination of them)

<u>case 3) </u>

K3 =k  (single body)

<u>case 4) </u>

K4 =(k*k/2k)+ 2k =k/2 +2k = 5k/2

(due to both series combination of the first two and parallel combination of the last)

<u>case 5) </u>

K5 =(k+2k)*3k/(k+2k+3k) = 3k/2

(due to the parallel combination of k and 2k and then a series combination with 3k)

Hence, the order of PE from greatest to lowest

case4 > case 2 > case 5 > case 3 >case 1

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A boy pushes on a wagon so that it accelerates at a rate of 0.50 m/s2. The wagon has a mass of 24 kg. What is the magnitude of t
IRISSAK [1]

Answer:

12N

Explanation:

Force acting on any body is equal to mass of body multiplied by acceleration produced in the body.

Its formula is

F = M*a

where F is the force acting on body

M is the mass of the body

a is the acceleration produced in the body

Unit of force is Newton represented by N

1 N is force acting on body of mass 1 kg which produces acceleration of 1m/s^2.

_____________________________________

Given

a = 0.50 m/s^2

M = 24 kg

therefore

F = 24*0.5 = 12 N

Thus,  magnitude of the boy's pushing force is 12 N.

4 0
4 years ago
Provided following are four different ranges of stellar masses. Rank the stellar mass ranges based on how many stars in each ran
elena-s [515]

Highest to lowest number:

-less than 1 solar mass

-between 1 and 10 solar masses

-between 10 and 30 solar masses

-between 30 and 60 solar masses

<h3>What is Stellar masses ?</h3>

Stellar mass is a phrase that is used by astronomers to describe the mass of a star.

  • It is usually enumerated in terms of the Sun's mass as a proportion of a solar mass ( M ☉). Hence, the bright star Sirius has around 2.02 M ☉.

  • Stellar masses are not fixed, although they change for single stars only on long periods.

Learn more about Stellar masses here:

brainly.com/question/1128503

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3 0
2 years ago
I rent a small high pressure water sprayer to clean the outside of my house. The sprayer works like a super soaker with a hose b
viva [34]

Answer:

1. 80,000 Pa

2. 11.3 m/s

3. 12.5 m/s

Explanation:

<u>Question 1</u>

Pressure, P=hg\rho

Where h is the height that water is to reach, g is gravitational constant and \rho is the density, in this case, we assume \rho of pure water as 1000 Kg/m^3

Assuming g=10 m/s^{2}

P=8*10*1000=80000 Pa

<u>Question 2</u>

Pressure can also be found by the formula

P=0.5v^{2}\rho where v is the velocity

Equating the new formula of pressure to the formula used in question 1 above

P=0.5v^{2}\rho=hg\rho

Notice that \rho is common hence

0.5v^{2}=hg

Making V the subject of the formula

v^{2}=2hg

v=\sqrt 2hg

In this case, h=8-1.6=6.4m and taking g as 10 m/s^{2}

v=\sqrt 2*10*6.4=11.3137085  m/s

Rounding off to 1 decimal place

v=11.3 m/s

<u>Question 3</u>

As already illustrated

v=\sqrt 2hg

Taking g as 9.8 and h now is 8m

v=\sqrt 2*8*9.8

v=12.52198067

Rounding off to 1 decimal place

v=12.5 m/s

6 0
3 years ago
The basic skill of advancing and controlling the ball to your feet while running.
Inessa05 [86]
<span>Direct Free Kick
Pass
<span>and Dribbling</span></span>
3 0
3 years ago
Earth-orbiting astronauts feel weightless in space because _____. Choose all that apply. 1 point They are in free-fall motion. T
STALIN [3.7K]

Answer:

They are in free-fall motion.

Explanation:

The Earth orbiting astronauts are falling at an acceleration that is the same or greater than the acceleration due to gravity i.e., 9.81 m/s². If you are continuously falling at this rate then you will feel weightless.

This same effect is felt while going down in an elevator. When you down in an elevator you feel that you are lighter and feel that something is pushing you up. Earth-orbiting astronauts feel the same effect but the accelration is greater hence they feel weightless.

5 0
3 years ago
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