There are times where the mass is less than the force of gravity or the gravitational pull. The gravitational pull will overpower the mass of the object, which is why you only notice the force of gravity and not the mass
Answer:
<h2>
650W/m²</h2>
Explanation:
Intensity of the sunlight is expressed as I = Power/cross sectional area. It is measured in W/m²
Given parameters
Power rating = 6.50Watts
Cross sectional area = 100cm²
Before we calculate the intensity, we need to convert the area to m² first.
100cm² = 10cm * 10cm
SInce 100cm = 1m
10cm = (10/100)m
10cm = 0.1m
100cm² = 0.1m * 0.1m = 0.01m²
Area (in m²) = 0.01m²
Required
Intensity of the sunlight I
I = P/A
I = 6.5/0.01
I = 650W/m²
Hence, the intensity of the sunlight in W/m² is 650W/m²
Answer:
4.33m
Explanation:
Power = work done/ time
work done = power × time =650 × 2 = 1300J
work done = force × distance
distance = work done/force
distance = 1300/300 = 4.33m
