<span>Total KE = KE (rotational) + KE (translational)
Moment of inertia of sphere is I = (2/5)mr^2
So KE (rotational) = (1/2) x I x w^2 = (1/2) x (2/5)mr^2 x w^2 = (1/5) x m x r^2 x w^2
KE (translational) = (1/2) x m x v^2 = (1/2) x m x (rw)^2 = (1/2) x m x r^2 x w^2
Hence KE = (1/5) x m x r^2 x w^2 + (1/2) x m x r^2 x w^2 = m x r^2 x w^2 ((1/5) + (1/2))
KE = (7/10) m x r^2 x w^2
Calculating the fraction of rotational kinetic energy to total kinetic energy,
= rotational kinetic energy / total kinetic energy
= (1/5) x m x r^2 x w^2 / (7/10) m x r^2 x w^2 = (1/5) / (7/10) = 2 / 7
The answer is 2 / 7</span>
Components connected in series are connected along a single path, so the same current flows through all of the components. If the light bulbs are connected in parallel, the currents through the light bulbs combine to form the current in the battery, while the voltage drop is across each bulb and they all glow.
Answer:
So, the radius of fifth Bohr orbital of hydrogen is 1. 3225 nm.
Explanation:
pls mark me brainless hope this helps loves x!
I think that this is false but I am not sure
