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Llana [10]
3 years ago
8

Tissues and organs worksheet answers describe the basic components of a tissue

Biology
1 answer:
Kazeer [188]3 years ago
4 0

<span>The most common bone disease is

osteomyelitis
osteoporosis
osteosarcoma
osteomalacia
rickets

</span>
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Design an experiment that answers the question “Does amylase break down starch?” Include the question, a hypothesis, a list of m
ivann1987 [24]
Amylase<span> is found in our saliva and is responsible for starting to </span>break down<span> the </span>starch<span> that we eat. So</span>amylase<span> is an enzyme that carries out the specific reaction of </span>breaking down starch<span> into a simple sugar.</span>Starch<span> is made up of many molecules of glucose (the simple sugar) joined in a chain.</span>
3 0
3 years ago
You want to determine whether short wings in fruit flies are the result of a dominant or recessive mutation. You cross a short-w
Natalka [10]

Answer:

a dominant mutation

Explanation:

A monohybrid testcross is a cross-breeding experiment used to determine if an individual exhibiting a dominant phenotype is homo-zygous dominant or heterozygous for a particular phenotypic trait (in this case, wing length). In a monohybrid testcross, a 1:1 phenotypic ratio shows that the dominant parental phenotype was a heterozygote for a single gene that has complete dominance. Moreover, a 3:1 ratio in the F2 is expected of a cross between heterozygous F1 individuals, which means that 75% of individuals with short wings have the dominant allele that masks the expression of the long-wing trait (i.e. the recessive allele).

4 0
3 years ago
Bacteria and other microbes can be used to "clean up" an oil spill by breaking down oil into carbon dioxide and water. Two sampl
SVETLANKA909090 [29]

Answer:

Sample A

T= 21.3% and A= 21.3%

G=28.7% and C= 28.7%

SAMPLE B

T=28.7% and  A= 28.7%

G= 21.3% and C= 21.3%

Sample A would have higher melting temperature

Explanation:

According to given information, sample A contains 21.3% thymine.

Percentage of adenine in sample A= 21.3% (Since adenine base pairs with thymine, so, adenine and thymine are present in equal amount in a double stranded DNA)

Total of A+T in sample A= 21.3 + 21.3 = 42.6%

G+ C content of sample A= 100-42.6= 57.4%

Percent G content of sample A = 57.4/2 = 28.7%

Percent C content of sample A = 28.7%

SAMPLE B:

According to the given information, sample B contains 28.7% thymine.

Therefore, percent of Adenine base in sample B= 28.7%

Total of A+T content in sample B= 28.7 + 28.7 = 57.4%

G + C content of the sample B = 100-57.4= 42.6%

Percent G content of the sample B= 42.6/2= 21.3%

Percent C content of sample B = 21.3%

There are three hydrogen bonds between a GC pair while there are only two hydrogen bonds between AT pair. The DNA content with higher GC content has higher melting temperature. Therefore, sample A would have higher melting temperature.

4 0
4 years ago
The food for dicot embryos is stored in the endospermcotyledons while food for monocot embryos is stored in the cotyledonsendosp
fiasKO [112]

Answer;

-Endosperm

-Cotyledon

The food for dicot embryos is stored in the endosperm while food for monocot embryos is stored in the cotyledons.

Explanation;

-The storage of food reserves in angiosperm seeds differs between monocots and dicots.

-Seeds need a supply of food to support the embryo plant until it can collect its own food. In monocots, there is usually a supply of food, called endosperm, inside the seed coat but separate from the cotyledon. In dicots, the cotyledons contain the endosperm.

3 0
3 years ago
Read 2 more answers
What most likely would happen to the animal populations after chemical spraying kills most of the region's mosquitoes and gnats,
Alisiya [41]
I'm going to go with A. This is because the population of frogs is definitely decreasing, as they are loosing food. Also, the frogs are prey for the snakes, and if there are no frogs for the snakes to eat, the population of snakes can go down, too.
Hope this helps!
5 0
3 years ago
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