Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
Answer: Mutualism is a relationship of two organisms wherein both organisms benefit from each other. ... Commensalism is a relationship of two organisms wherein one organism benefit from the other with neither harm nor benefit to the other
Answer:
a. hox genes.
Explanation:
HOX genes have the following functions:
- HOX genes are the homeobox subset.
- They specify the areas of the embryo's body plan along the animal head-tail axis.
- They are encoding Hox proteins that specify the position characteristics and ensure that the right structures form at the right position in the body.
- They regulate high-level executive genes, such as transcription factors and intracellular signaling molecules, which adhere, number, form, and growth to cells.
The vertebrates are highly preserved.
The clusters and other genes occur uninterrupted.
Evolutionary, the heterogeneous regulatory areas between the genes most previously present are larger and more preserved than those present at the other ends of the clusters.
The characteristical feature is that these are homeodomain proteins with a highly preserved area of DNA binding encoded with homeobox gens.
