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tigry1 [53]
3 years ago
11

A student rolled two six-sided number cubes several times. the numbers below are the sums of the numbers she rolled. Which histo

gram represents the data?

Mathematics
1 answer:
Ghella [55]3 years ago
8 0
If the two given six-sided number cubes contains the typical numbers starting from 1 to 6, the sum of the numbers will most likely be in the range of 6-9. Thus, for this item, the histogram that would best represent the scenario is the second column. 
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Ms.jones has a decorative pyramid that sits on her fireplace mantle .the base is an equilateral triangle with an area of 6 squar
levacccp [35]

ion know but 7 :Ddfsdf


8 0
3 years ago
What is the absolute value of 2 1/2<br><br> Write your answer as a mixed number.
Greeley [361]

Answer:

it is 2 1/2

Step-by-step explanation:

I hope this helps

6 0
3 years ago
(11 – 3)2 x (-12) = 4
skelet666 [1.2K]
Hope that’s right!!!
6 0
3 years ago
Read 2 more answers
Herbert has sold 99, 37, 86, and 73 copeirs in the last 4 months, respectivly. How many copiers will he need to sell this month
jolli1 [7]

Answer:

Therefore 80 ceperies will he need to sell this month.

Step-by-step explanation:

Average: Average is the ratio of sum of all numbers to the total number present in the data.

Given that Herbert has sold 99, 37, 86 and 73 copeirs in the last 4 months.

Let he need to sell x copeirs in this month.

According to the problem,

\frac{99+37+86+73+x}{5}=75

⇒ 99+37+86+73+x= 75×5

⇒295 + x= 375

⇒x = 375 - 295

⇒ x= 80

Therefore 80 ceperies will he need to sell this month.

3 0
3 years ago
Use spherical coordinates to find the volume of the region that lies outside the cone z = p x 2 + y 2 but inside the sphere x 2
Harman [31]

I assume the cone has equation z=\sqrt{x^2+y^2} (i.e. the upper half of the infinite cone given by z^2=x^2+y^2). Take

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

The volume of the described region (call it R) is

\displaystyle\iiint_R\mathrm dx\,\mathrm dy\,\mathrm dz=\int_0^{2\pi}\int_0^{\sqrt2}\int_{\pi/4}^\pi\rho^2\sin\varphi\,\mathrm d\varphi\,\mathrm d\rho\,\mathrm d\theta

The limits on \theta and \rho should be obvious. The lower limit on \varphi is obtained by first determining the intersection of the cone and sphere lies in the cylinder x^2+y^2=1. The distance between the central axis of the cone and this intersection is 1. The sphere has radius \sqrt2. Then \varphi satisfies

\sin\varphi=\dfrac1{\sqrt2}\implies\varphi=\dfrac\pi4

(I've added a picture to better demonstrate this)

Computing the integral is trivial. We have

\displaystyle2\pi\left(\int_0^{\sqrt2}\rho^2\,\mathrm d\rho\right)\left(\int_{\pi/4}^\pi\sin\varphi\,\mathrm d\varphi\right)=\boxed{\frac43(1+\sqrt2)\pi}

4 0
3 years ago
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