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Anettt [7]
3 years ago
12

How do I solve this question?

Mathematics
1 answer:
weqwewe [10]3 years ago
6 0

Answer:

1,-3

Step-by-step explanation:

The solution to a graph is where the two lines interscet and this graph intersects at the points 1, -3

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Is ABC DEF? If so, identify the similarity postulate or theorem that applies.
VladimirAG [237]

We are given traingle ABC and Triangle DEF.

Angle <A is congruent to Angle <D

Angle <B is congruent to Angle <E

Angle <C is congruent to Angle <F.

If two pairs of corresponding angles are congruent to each other, then the triangles are similar by Angle-Angle Similarity.

<em>By Angle-Angle similarity postulate triangle ABC and triangle DEF are similar.</em>

Therefore, option C is correct option.

<h3>C. Similar - AA.</h3>
7 0
3 years ago
Read 2 more answers
1/4( x - 1 ) + 3x = 2 <br>solve the equation
Dmitriy789 [7]
The answer is x = 9/13
Hope in helped
3 0
2 years ago
How to make 2700 and 600 a fraction
devlian [24]
I think I may be missing something ... I don't completely understand your question. 
All you need to make a fraction is two numbers and a bar.  The bar can be either
horizontal or slanty.  Then you write one number on top and the other number on
the bottom, and bada-bing, you have a fraction.

You can make fractions like

             2700 / 600
                 27 / 6         
                   9 / 2           (all 3 of these have the same value)

             600 / 2700
                 6 / 27         
                 2 / 9              (all 3 of these have the same value) 
8 0
3 years ago
50*50+60+90+40-60-43-89-30-34+12​
tensa zangetsu [6.8K]
The answer is 2446.
5 0
3 years ago
Read 2 more answers
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD=√2 cm.
Zielflug [23.3K]

Given that triangle ABC is right angle triangle. CD is altitude such that AD=BC

ABC is a right angle triangle so apply Pythogorean theorem

AC^{2} + BC^{2} = AB^{2}

AC^{2} + AD^{2} = AB^{2}      (Given that AD = BC)

AC^{2} + AD^{2} = 3^{2}      (Given that AB=3)

AC^{2} + AD^{2} = 9 ...(i)

ADC is a right angle triangle so apply Pythogorean theorem

AD^{2} + CD^{2} = AC^{2}

AD^{2}+(\sqrt{2})^2= AC^{2}

AD^{2}+2= AC^{2}

AD^{2}=AC^{2} -2 ...(ii)


Plug value (ii) into (i)

AC^{2} + AC^{2}-2 = 9

2AC^{2} -2=9

2AC^{2} =11

AC^{2} =\frac{11}{2}

AC=\sqrt{\frac{11}{2} }


Hence final answer is AC=\sqrt{\frac{11}{2} }

8 0
3 years ago
Read 2 more answers
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