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3 years ago

PLZ QUICK!!

Mathematics

2 answers:

Kruka [31]3 years ago

7 0

Answer:

SM = MO

Step-by-step explanation:

thats the only one i know, but it is correct

Norma-Jean [14]3 years ago

5 0

Answer:

Part 1) A>T

Part 2) MO<SM

Part 3) SM=MO

Step-by-step explanation:

Part 1)

If SM> MO

then

m<A>m<T -------> The measure of angle A is an obtuse angle

Part 2)

If A> T

then

SM> MO -----> see part 1)

rewrite

MO<SM

Part 3)

If A=T

then

Triangle ASM and triangle TMO are congruent by SAS similarity postulate

therefore

SM=MO

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Read 2 more answers

area of rectangular field is 726 sq m if the ratio between its length and breadth is 3:2' find the length and breadth.

ale4655 [162]

Answer:

length = 3x = 3 × 11 = 33 m

breadth = 2x = 2 × 11 = 22 m

Step-by-step explanation:

here's the solution :-

let's take the ratio constants be x

so, length = 3x

breadth = 2x

And, we know that area of rectangle =

length × breadth

So,

=》

$3x \times 2x = 726$

=》

$6 {x}^{2} = 726$

=》

${x}^{2} = \frac{726}{6}$

=》

${x}^{2} = 121$

=》

$x = \sqrt{121}$

=》

$x = 11$

so, length = 3x = 3 × 11 = 33 m

breadth = 2x = 2 × 11 = 22 m

4 0

3 years ago

If A^2=A, which matrix is matrix A

Ronch [10]

Consider all options:

$\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] \cdot \left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] =\left[\begin{array}{cc}5\cdot 5+5\cdot (-4)&5\cdot 5+5\cdot (-4)\\-4\cdot 5+(-4)\cdot (-4)&-4\cdot 5+(-4)\cdot (-4)\end{array}\right]=$

$=\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right].$

This option is true.

$\left[\begin{array}{cc}6&5\\5&6\end{array}\right] \cdot \left[\begin{array}{cc}6&5\\5&6\end{array}\right] =\left[\begin{array}{cc}6\cdot 6+5\cdot 5&6\cdot 5+5\cdot 6\\5\cdot 6+6\cdot 5&5\cdot 5+6\cdot 6\end{array}\right]=$

$=\left[\begin{array}{cc}61&60\\60&61\end{array}\right].$

This option is false.

$\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+(-0.5)\cdot (-0.5)&0.5\cdot (-0.5)+(-0.5)\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot (-0.5)+0.5\cdot 0.5\end{array}\right]=$

$=\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right].$

This option is true.

$\left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+0.5\cdot (-0.5)&0.5\cdot 0.5+0.5\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot 0.5+0.5\cdot 0.5\end{array}\right]=$

$=\left[\begin{array}{cc}0&0.5\\-0.5&0\end{array}\right].$

This option is false.

$\left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] \cdot \left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] =\left[\begin{array}{cc}-6\cdot (-6)+(-6)\cdot 5&-6\cdot (-6)+(-6)\cdot 5\\5\cdot (-6)+5\cdot 5&5\cdot (-6)+5\cdot 5\end{array}\right]=$