(24y^5)/(15x^8) * 4x^4/(8y²)
<span>Reduce the common factors for the numerator and denominator and multiply the fractions altogether to get... </span>
<span>24/8 * y^(5 - 2) * 4/15 * 1/x^(8 - 4) </span>
<span>= 3y³ * 4/15 * 1/x^4 </span>
<span>= 4y³/(5x^4) </span>
<span>I hope this helps!</span>
Answer:
He can use the factors of 36 to determine the number of groups he can divide the class into such that they are equal.
The Factors (excluding 1) are;
2, 3, 4, 6, 9, 12, 18
Using these therefore he can divide them;
- Into 3 groups each with 12 people.
- Into 4 groups each with 9 people.
- Into 6 groups each with 6 people.
- Into 9 groups each with 4 people.
- Into 12 groups each with 3 people.
The result follows directly from properties of modular arithmetic:
That is,
means we can write 
for some integer 
. Then
and taken mod 12, the first term goes away, so
etc
Answer:
256m^2
Step-by-step explanation:
you can cut up the figure.
A1=bh
A1= 24x8
A1=192m^2
A2=bh
A2= bh
A2=8x8
A2=64m^2
A1+A2= Atotal
A=192+64
A=256m^2
Answer:
4
Step-by-step explanation:
n/6+2
Let n = 12
12/6 +2
Division first
2 +2
4
