3 years ago

Write the equation of a line that is parallel to y=0.6x+3 and passes through the point (-3,-5)

1 answer:

6 0

Answer:y=0.6x-3.2

Step-by-step explanation: The equation of a line is (y-y0)=m*(x-x0). The slope (m) of the original line is 0.6 and must be the same slope for the new line. y0 and x0 are the coordinates of a point where the line passes through. x0=-3 and y0=-5.

Doing the maths:

(y+5)=0.6*(x+3)

y=0.6x+1.8-5

y=0.6x-3.2

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