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sergiy2304 [10]

3 years ago

11

What is the relationship between two coplanar lines that are perpendicular to the same line?

2 answers:

Charra [1.4K]3 years ago

6 0

Answer:

I'm sorry for this but I'll help you if you help me?

grigory [225]3 years ago

3 0

Answer:

If two lines are perpendicular to the same line, then the two lines are parallel, and if two lines are parallel, then their slopes are equal

Step-by-step explanation:

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Assoli18 [71]

39 miles. If d=rt and the rate is 16 mph and the time is 3 hours then 16 times 3 gives the distance of 39 miles. I could be wrong but that is what I would have done. I’m not sure if there are answer choices or not

4 0

3 years ago

Put y+7=1/2(x+2) in standard form <br> Standard form: Ax+By=C

My name is Ann [436]

$y+7=\frac{1}{2}(x+2)\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\2y+14=x+2\ \ \ \ |subtract\ x\ and\ 2\ from\ both\ sides\\\\-x+2y+14-2=0\\\\-x+2y+12=0\ \ \ \ \ |change\ signs\\\\\boxed{x-2y-12=0}$

4 0

3 years ago

Solve for x <br> 8+4x=-16

saw5 [17]

Answer:

x = -6

Step-by-step explanation:

8 + 4x = -16

4x = -16 - 8

4x = -24

x = -24/4

x = -6

5 0

2 years ago

Read 2 more answers

How much is 3 over 15 plus 1 over 3

REY [17]

Answer:

8/15

Step-by-step explanation:

Well to add fractions you have to have the same denominator so you would multiply your 1/3 by 5 to be 5/15 then you can add.

3/15 + 5/15 = 8/15

4 0

3 years ago

Read 2 more answers

Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number

sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable <em>X</em> is:

$E(X)=\sum x\cdot P(X=x)$

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner: 1 2 3 4 5 6

Amount earned (<em>X</em>): $1 $4 $7 $10 -$8.75 -$8.75

Probability: 1/6 1/6 1/6 1/6 1/6 1/6

Compute the expected value of <em>X</em> as follows:

$E(X)=\sum x\cdot P(X=x)$

$=(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})$

$=\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}$

$=\frac{1+4+7+10-8.75-8.75}{6}$

$=0.75$

Thus, the expected value of playing the game is $0.75.

5 0

3 years ago