Question

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Answer:

See below.

Step-by-step explanation:

The quadratic formula is $x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$. Here a=1, b=1, and c=-4.

Substitute and you'll have:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-1+/-\sqrt{1^2-4(1)(-4)} }{2(1)}=\frac{-1+/-\sqrt{1+16} }{2)}=$

$\frac{-1+/-\sqrt{17} }{2}$