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r-ruslan [8.4K]
3 years ago
6

3. A rocket is launched vertically from the ground with an initial velocity of 64 ft / sec . ( a ) Write a quadratic function h

( t ) that shows the height , in feet , of the rocket t seconds after it was launched . ( b ) Graph h ( t ) on the coordinate plane . ( c ) Use your graph from Part 3 ( b ) to determine the rocket's maximum height , the amount of time it took to reach its maximum height , and the amount of time it was in the air . Answer :

Mathematics
2 answers:
lys-0071 [83]3 years ago
6 0

Answer:

See below.

Step-by-step explanation:

The rocket's  flight is controlled by its initial velocity and the acceleration due to gravity.

The equation of motion is h(t) = ut + 1.2 g t^2 where  u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.

(a) h(t) = 64t  - 1/2*32 t^2

h(t) = 64t - 16t^2.

(b) The graph will be a parabola which opens downwards  with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).

The y-axis is the height of the rocket and the x-axis  gives the time.

Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.

Advocard [28]3 years ago
5 0
Yeah the person above is right
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The number in the ones place= X
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Original placement of numbers=10y+x
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140-14-36=10x-x+10x-x
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