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3 years ago

1.5 units

Mathematics

1 answer:

scoray [572]3 years ago

3 0

Answer:

3 units

Step-by-step explanation:

There are 3 squares between them.

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X^2-x-42<br> what is the fractored forms

igomit [66]

The factored forms of that is (x + 6) (x - 7).

If you have any questions then please leave a comment. Good luck!

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3 years ago

Construct a triangle whose sides are 3 in., 1 1/2 in., 2 3/8 in., 2 in., 3 1/2 in.

Luda [366]

That's 5 lengths for a three sided shape... Are you sure that is the instructions?

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3 years ago

Giving brainliest and max rating.

Yanka [14]

Given:

The cost of each carnival ticket is $5.

To find:

The equation, table of values and graph for the given problem.

Solution:

Let x be the number of tickets and y be the total money spent on tickets.

Cost of one ticket = $5

Cost of x tickets = $5x

So, total cost is

$y=5x$

The required equation is $y=5x$ .

At x=1,

$y=5(1)$

$y=5$

At x=2,

$y=5(2)$

$y=10$

At x=3,

$y=5(3)$

$y=15$

The required table of values is

x y

1 5

2 10

3 15

So, the required table of values is table A.

From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.

So, the required graph is graph B.

Since the required answers are $y=5x$ , table A, graph B, therefore the correct option is B.

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2 years ago

A pickup truck carrying 10 to the 3rd power identical bricks weighs 6,755 pounds. If the empty truck weighs 6,240 pounds, what i

Aleks04 [339]

Answer:

The answer is that each brick weights .515 pounds.

Step-by-step explanation:

10 to the 3rd power is 10^3 = 1000 bricks.

The weight of the full truck minus the weight of the empty truck is the weight of the bricks:

6755 - 6240 = 515 pounds of bricks

Pounds per brick:

515 / 1000 = .515 pounds per brick.

Hope this helps! Have a great day!

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3 years ago

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

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1 year ago